Ask question

Ask question

All categories

2 years ago

15

80 foot-pounds of work is needed to move the sofa in Tyler's apartment. Which of the following statements is true?

1 answer:

erastova [34]2 years ago

3 0

D is the correct answer
hop it helped.

You might be interested in

A hydraulic jack is used to lift a car in order to change a tire. The car exerts a force of 9,800 N toward the ground due to the

KiRa [710]

To begin to lift the car, a hydraulic jack must produce <em>more than 9,800N</em> of force.

To keep the car in position once it is lifted, the jack must produce <em>exactly 9,800N</em> of force.

6 0

1 year ago

Read 2 more answers

Which form or radiation has the greater frequency?<br> UV radiation or violet light?

Klio2033 [76]

Ultra violet has a greater frequency.

3 0

1 year ago

Read 2 more answers

An electron (charge −e=−1.60×10−19C−e=−1.60×10−19C) is at rest at a distance 1.00×10−10 m 1.00×10−10m from the center of a nucle

shtirl [24]

Answer:

$-9.45\times10^{-16} \text{ J}$

Explanation:

According to Coulomb's law, the force of attraction between two point charges, $q_1$ and $q_2$ , separated by a distance $d$ is given by

$F = k\dfrac{q_1q_2}{d^2}$

$k$ is a constant with a value of $9\times10^9\text{ F/m}$ .

When we substitute the values from the question,

$F = (9\times10^9\text{ F/m})\dfrac{(-1.60\times10^{-19} \text{ C})\times(+1.31\times10^{-17}\text{ C})}{(1.00\times10^{-10}\text{ m})^2} = -1.89\times10^{-6} \text{ N}$

This value is negative because it is in a direction towards the positive charge.

The work done in moving the electron from the nucleus is

$W = F\times r$

$W = (-1.89\times 10^{-6} \text{ N})\times(5.00\times10^{-10}\text{ m}) = -9.45\times10^{-16} \text{ J}$

This is negative because work is done on the electron, not by it.

3 0

1 year ago

A particle (charge = 5.0 μC) is released from rest at a point x = 10 cm on the x-axis. If a 5.0-μC charge is held fixed at the o

victus00 [196]

Answer:

Explanation:

Given

Two charges with charge $Q=5\ \mu C$

When the first charge is at $x=10\ cm$ on the x-axis and another at x=0 (origin)

there is only Potential Energy

Total Energy(E)=Kinetic Energy(K)+Potential Energy(U)

$U_i=\frac{kQ\cdot Q}{r}$

$U_i=\frac{9\times 10^9\times (5\times 10^{-6})^2}{0.1}$

$U_i=2.25\ J$

$E=2.25$

When First charge is at $x=90$

There will be both Kinetic energy and potential Energy

$U_f=\frac{kQ\cdot Q}{r}$

$U_f=\frac{9\times 10^9\times (5\times 10^{-6})^2}{0.9}$

$U_f=0.25\ J$

As total Energy is constant therefore Kinetic Energy is

$k=E-U_f$

$k=2.25-0.25=2\ J$

4 0

1 year ago

A capacitor with initial charge q0 is discharged through a resistor. What multiple of the time constant τ gives the time the cap

fiasKO [112]

Answer: a) 0.13*τ ; b) 2.08*τ

Explanation: In order to explain the discharg of a capacitor through a resistor, we have to consider the following:

Q(t)=Qo* exp(-t/τ) for a lose of 1/8-th of its charge

in this case, Q(t)=7/8*Qo=7/8*exp(-t/τ)

ln(7/8)*τ=-t

then, t= -ln(7/8)*τ =0.13

For a lose of 7/8 th of its charge , we have

Q(t)=1/7*Qo*exp(-t/τ)

t=-ln(1/8)*τ=2.08

5 0

1 year ago