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NISA [10]
2 years ago
14

Consider as a system the gas in a vertical cylinder; the cylinder is fitted with a piston on which a number of small weights are

placed. The initial pressure is 200 kPa, and the initial volume of the gas is 0.04 m3 . (a) Let a Bunsen burner be placed under the cylinder, and let the volume of the gas increase to 0.1 m3 while the pressure remains constant. Calculate the work done by the system during this process. (b) Consider the same system and initial conditions, but at the same time that the Bunsen burner is under the cylinder and the piston is rising, remove weights from the piston at a rate such that, during the process, the temperature of the gas remains co
Physics
1 answer:
Amiraneli [1.4K]2 years ago
5 0

Answer:

Explanation:

a ) At constant pressure , work done = P x Δ V

= 200 x 10³ x ( .1 - .04 )

= 12 x 10³ J .

b )

At constant temperature work done

= n RT ln v₂ / v₁

= PV ln v₂ / v₁

= 200 x 10³ x .04 ln .1 / .04

8 x 10³ x .916

= 7.33 x 10³ J .

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The muzzle velocity of a 50.0g shell leaving a 3.00 kg rifle is 400m/s what is the recoil velocity of the rifle
serg [7]

Here if we consider bullet and gun as a system then we can say that momentum of the system will remain conserved

so we will have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

now we know that

m_1 = 50 g = 0.050 kg

m_2 = 3 kg

v_{1i} = v_{2i} = 0

v_{1f} = 400 m/s

now we will have

0.050(0) + 3(0) = 0.050(400) + 3(v)

20 + 3v = 0

v = - \frac{20}{3} = - 6.67 m/s

so gun will recoil with speed 6.67 m/s

6 0
2 years ago
Un cable está tendido sobre dos postes colocados con una separación de 10 m. A la mitad del cable se cuelga un letrero que provo
lisabon 2012 [21]

Answer:

El peso del cartel es 397,97 N

Explanation:

La tensión dada en cada segmento del cable = 2000 N

El desplazamiento vertical del cable = 50 cm = 0,5 m

La distancia entre los polos = 10 m

La posición del letrero en el cable = En el medio = 5

El ángulo de inclinación del cable a la vertical = tan⁻¹ (0.5 / 5) = 5.71 °

El peso del letrero = La suma del componente vertical de la tensión en cada lado del letrero

El peso del signo = 2000 × sin (5.71 grados) + 2000 × sin (5.71 grados) = 397.97 N

El peso del signo = 397,97 N.

8 0
2 years ago
160 students sit in an auditorium listening to a physics lecture. Because they are thinking hard, each is using 125 W of metabol
anastassius [24]

Answer:

minimum power should be used to operate the air conditioner is 4000 W

Explanation:

given data

students  n = 160

power p = 125 W

COP = 5.0

to find out

what minimum power should be used

solution

we know the COP formula that is given below

COP = students × power  / minimum power

minimum power = n × p / COP

put all value

minimum power = n × p / COP

minimum power = 160 × 125 / 5

minimum power = 4000 W

minimum power should be used to operate the air conditioner is 4000 W

8 0
2 years ago
An orange of mass 3kg falls from a height 50m. When its height is H, its speed is
MArishka [77]

Answer:

(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²

Explanation:

Initially, the orange has only gravitational potential energy.

As the orange falls, it has a combination of potential energy and kinetic energy.

Energy is conserved, so initial energy = final energy:

PE₀ = PE + KE

mgH₀ = mgH + ½ mv²

gH₀ = gH + ½ v²

Plugging in values:

(10 m/s²) (50 m) = (10 m/s²) H + ½ (4 m/s)²

8 0
2 years ago
A boy can accelerate at 1.00 m/s 2 over a short distance. If the were to take an energy pill and suddenly have the ability to ac
VikaD [51]
We know that:
F = ma,
so
F/a = constant
F₁/a₁ = F₂/a₂
F₂ = F₁ x 5.6 / 1
F₂ = 5.6F₁

If F₁ = 45 N,
F₂ = 5.6 x 45
= 252 N
4 0
2 years ago
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