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Sav [38]
2 years ago
10

A cube with edges exactly 2 cm long is made of material with a bulk modulus of 3.5 x 109 n/m2. when it is subjected to a pressur

e of 3.0 x 105 pa its volume is:
Physics
1 answer:
Igoryamba2 years ago
5 0

As we know by the formula of bulk modulus

B = \frac{\Delta P}{-\Delta V/V}

now we can rearrange it as

\Delta V/V = -\frac{\Delta P}{B}

V_f - V = -V\frac{\Delta P}{B}

now the final volume after pressure is applied is given as

V_f = V(1 - \frac{\Delta P}{B})

now we know that

\Delta P = 3 \times 10^5 Pa

V = 2^3 cm^3 = 8 cm^3

B = 3.5 \times 10^9 N/m^2

now plug in all data

V_f = 8(1 - \frac{3 \times 10^5}{3.5 \times 10^9})

V_f = 7.999 cm^3

so volume is above after pressure is applied over it

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Answer:d

Explanation:

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Work done by block on the spring is equal to change in elastic potential energy

i.e. Work done by block W=\frac{1}{2}kx^2

therefore spring will also done an equal opposite amount of work on the block in the absence of external force

Thus work done by spring on the block W=-\frac{1}{2}kx^2

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2 years ago
If Emily throws the ball at an angle of 30∘ below the horizontal with a speed of 14m/s, how far from the base of the dorm should
liubo4ka [24]

Emily throws the ball at 30 degree below the horizontal

so here the speed is 14 m/s and hence we will find its horizontal and vertical components

v_x = 14 cos30 = 12.12 m/s

v_y = 14 sin30 = 7 m/s

vertical distance between them

\delta y = 4 m

now we will use kinematics in order to find the time taken by the ball to reach at Allison

\delat y = v_y *t + \frac{1}{2} at^2

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now we will have

4 = 7 * t + \frac{1}{2}*9.8 * t^2

now solving above quadratic equation we have

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now in order to find the horizontal distance where ball will fall is given as

d = v_x * t

here it shows that horizontal motion is uniform motion and it is not accelerated so we can use distance = speed * time

d = 12.12 * 0.44 = 5.33 m

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8 0
2 years ago
Devonte pushes a wheelbarrow with 830 W of power. How much work is required to get the wheelbarrow across the yard in 11 s? Roun
xxMikexx [17]

Answer: 9130 joules

Explanation:

Workdone by wheelbarrow = ?

Time = 11 seconds

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Recall that power is the rate of doing work. Thus, power is workdone divided by time taken.

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Workdone = 830 watts x 11 seconds

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Thus, 9130 joules of work is required to get the wheelbarrow across the yard.

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2 years ago
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yawa3891 [41]
The partial pressure of the O2 is 36.3 kiloPascal when the air pressure in the mask is 110 kiloPascal based on the isotherm relation. This problem can be solved by using the isotherm relation equation which stated as Vx/Vtot = px/ptot, where V represents volume, p represents the pressure, x represents the partial gas, and tot represents the total gas<span>. Calculation: 33/100 = px/110 --> px = 36.3</span>
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Answer:

As shown in the attachment

Explanation:

The detailed steps and mathematical assumptions and manipulation is as shown in the attachment.

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