To calculate the acceleration of the wooden block, we use the expression F=ma where F is the force applied, m is the mass of the object and a is the acceleration. We calculate as follows:
F = ma
4.9 = 0.5a
a = 9.8
Hope this answers the question. Have a nice day.
Answer:
(a) k =
(b) τ =
∝
Explanation:
The moment of parallel pipe rotating about it's axis is given by the formula;
I =
---------------------------------1
(a) The kinetic energy of a parallel pipe is also given as;
k =
--------------------------------2
Putting equation 1 into equation 2, we have;
k = 
k =
(b) The angular momentum is given by the formula;
τ = Iw -----------------------3
Putting equation 1 into equation 3, we have
τ = 
But
τ = dτ/dt =
------------------4
where
dw/dt = angular acceleration =∝
Equation 4 becomes;
τ =
∝
Complete Question:
Check the circuit in the file attached to this solution
Answer:
Total current = 0.056 A(From left to right)
Explanation:
Let the current in loop 1 be I₁ and the current in loop 2 be I₂
Applying KVL to loop 1
30 - (I₁ - I₂)500 + I₂R + 15 = 0
45 - 500I₁ - 500I₂ + RI₂ = 0
I₁ = 30mA = 0.03 A
45 - 500(0.03) - 500I₂ + RI₂ = 0
30 -500I₂ + RI₂ = 0...............(1)
Applying kvl to loop 2
-RI₂ - 15 + 10 - 400I₁ = 0
-RI₂ = 5 + 400*0.03
RI₂ = -17 ................(2)
Put equation (2) into (1)
30 -500I₂ -17 = 0
-500I₂ = 13
I₂ = -13/500
I₂ = -0.026 A
The total current in the 500 ohms resistor = I₁ - I₂ = 0.03+0.026
Total current = 0.056 A
The current will flow from left to right
Answer:
The answer is 3.
Explanation:
The answer to this question can be found by applying the right hand rule for which the pointer finger is in the direction of the electron movement, the thumb is pointing in the direction of the magnetic field, so the effect that this will have on the electrons is the direction that the middle finger points in which is right in this example.
So as a result of the magnetic field directed vertically downwards which is at a right angle with the electron beams, the electrons will move to the right and the spot will be deflected to the right of the screen when looking from the electron source.
I hope this answer helps.