A wind turbine with a rotor diameter of 40 m produces 90 kW of electrical power when the wind speed is 8 m/s. The density of air
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Answer:
The energy of the system is 15 J.
Explanation:
Given that,
Energy E = 2.5 J
Amplitude = 10 cm
We need to calculate the spring constant
Using formula of mechanical energy of the system
Put the value into the formula
If the block is replaced by a block with twice the mass of the original block
Amplitude = 6 cm
We need to calculate the energy
Using formula of mechanical energy
Put the value into the formula
Hence, The energy of the system is 15 J.
(a) The diffraction decreases
The formula for the diffraction pattern from a single slit is given by:
where
is the angle corresponding to nth-minimum in the diffraction pattern, measured from the centre of the pattern
n is the order of the minimum
is the wavelength
a is the width of the opening
As we see from the formula, the longer the wavelength, the larger the diffraction pattern (because increases). In this problem, since the wavelength of the signal has been decreased from 54 cm to 13 mm, the diffraction of the signal has decreased.
(b)
The angular spread of the central diffraction maximum is equal to twice the distance between the centre of the pattern and the first minimum, with n=1. Therefore:
in this case we have
is the wavelength
is the width of the opening
Solving the equation, we find
So the angular spread of the central diffraction maximum is twice this angle:
(c)
Here we can apply the same formula used before, but this time the wavelength of the signal is
so the angle corresponding to the first minimum is
So the angular spread of the central diffraction maximum is twice this angle: