Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The value is 
Explanation:
From the question we are told that
The length of the stretcher is 
The weight of the stretcher is 
The weight for Wayne is 
The distance of center of gravity for Wayne from Chris is 
Generally taking moment about the first end where Chris is
=> upward moment
Here
is the force applied by Jamie
Generally taking moment about the second end where Jamie is
=> downward moment
Generally at equilibrium , the upward moment is equal to the downward moment

=> 
=> 
Answer:
428.59 N
Explanation:
Buoyant force,
where V is volume, g is gravitational constant and \rho is density
where
is upward force


where
is the density of hippo

Using g as 9.81

Therefore, the upward force=428.59 N
Answer:
v₀ₓ = 15 m / s,
= 5.2 m / s
v = 15.87 m / s
, θ = 19.1
Explanation:
This is a projectile launch problem. The horizontal speed that is constant throughout the entire path is worth 15 m / s, instead the vertical speed changes in value due to the acceleration of gravity, let's look for the initial vertical speed
Vy² =
² - 2 g y
² =
² + 2 g y
= √ (
² + 2 gy
Let's calculate
= √ (1.25² + 2 9.8 1.3)
= √ (27.04)
= 5.2 m / s
The initial speed can be calculated by the initial speed
v = √ v₀ₓ² +
²
v = RA (15² + 5.2²)
v = 15.87 m / s
We look for the angle with trigonometry
tan θ = voy / vox
θ = tan⁻¹ I'm going / vox
θ = tan⁻¹ 5.2 / 15
θ = 19.1
The answer is
v₀ₓ = 15 m / s
= 5.2 m / s
The angular velocity of the orbit about the sun is:
w = 1 rev / year = 1 rev / 3.15 × 10^7 s
Now in 1 rev there is 360° or 2π rad, therefore:
w = 2π rad / 3.15 × 10^7 s
To convert in linear velocity, multiply the rad /s by the
radius:
v = (2π rad / 3.15 × 10^7 s) * 93,000,000 miles
<span>v = 18.55 miles / s = 29.85 km / s</span>
The correct answer would be B. It is the compound Na2S that forms an ionic bond from the given ion above. From the choices, it is the only compound that exist and is available. Metals cannot react with another metal as well as nonmetal to nonmetal.