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mestny [16]
2 years ago
12

In an experiment the chemical reaction between a piece of aluminum foil and Copper(II)Chloride solution in a beaker is observed.

The Aluminum seems to disapear over time. The balanced chemical equation is given by: 2 Al + 3 CuCl ⇒3 Cu +2 AlCl3
Can you predict the outcome of the same experiment when Aluminum is replaced with a more reactive element such as Silver?

A) No reaction would occur.
B) The silver would disappear but no solid precipitate would form.
C) The silver would disappear and a silver solid precipitate would form.
D) The silver would disappear and a brownish red solid precipitate would form.

Hint: What would the new product be?

Physics
2 answers:
telo118 [61]2 years ago
8 0
When Ag(silver) reacts with CuCl2, Ag displaces Cu from CuCl2 and forms AgCl which is soluble and brownish red solid precipitate is left in the solution. 

Hence option D is correct.
Hope this helps!
bearhunter [10]2 years ago
6 0

Answer: A) No reaction would occur.

Explanation:

Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

Example: 2Al+3CuCl\rightarrow 3Cu+2AlCl_3

Thus When aluminium is treated with copper chloride ,aluminium being more reactive than copper displaces copper from its salt solution and thus produce aluminium chloride.

But when aluminum is replaced by silver, o reaction would occur as silver is less reactive than copper and hence would not be displace it from its salt solution.

Ag+CuCl\rightarrow {\text {no reaction}}

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Chris and Jamie are carrying Wayne on a horizontal stretcher. The uniform stretcher is 2.00 m long and weighs 100 N. Wayne weigh
PIT_PIT [208]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value is F_j  =  550\ N

Explanation:

From the question we are told that

   The length of the stretcher is  d =  2.0 \  m

    The weight of the stretcher is W  =  100 \  N

    The weight for Wayne is  W_w =  800 \ N

     The distance of  center of gravity for Wayne from Chris is c_w = 75 cm  =  0.75 \ m

Generally taking moment about the first end where Chris is

         F_j *  d              => upward moment

Here F_j is the force applied by Jamie

Generally  taking moment about the second end where Jamie is

      W *  ( \frac{d}{2} ) +  W_w * (d - c_w)      => downward moment

Generally at equilibrium , the upward moment is equal to the downward moment

     F_j *  d = W *  ( \frac{d}{2} ) +  W_w * (d - c_w)

=>   F_j *  2  = 100 *  ( \frac{ 2}{2} ) +  800 * (2 - 0.75)

=>    F_j  =  550\ N

3 0
2 years ago
Hippos spend much of their lives in water, but amazingly, they don’t swim. manatees, They have, like little very body fat. The d
kenny6666 [7]

Answer:

428.59 N

Explanation:

Buoyant force, B=Vg\rho where V is volume, g is gravitational constant and \rho is density

B+F_{upward}=mg where F_{upward} is upward force

Vg\rho_{w}+F_{upward}=mg

F_{upward}=mg- Vg\rho_{w}

F_{upward}=g(mg- V\rho_{w})=g(m-m\frac {\rho_{w}{\rho_{hippo}} where \rho_{hippo} is the density of hippo

F_{upward}=mg(1-\frac {\rho_{w}}{\rho_{hippo}})

Using g as 9.81

F_{upward}=1500*9.81*(1-1000/1030)= 428.5922 N

Therefore, the upward force=428.59 N

3 0
2 years ago
A punted football is observed to have velocity components vhorizontal = 15 m/s to the right and vvertical = 1.25 m/s directed do
enot [183]

Answer:

v₀ₓ = 15 m / s,  v_{oy} = 5.2 m / s

v = 15.87 m / s ,   θ = 19.1

Explanation:

This is a projectile launch problem. The horizontal speed that is constant throughout the entire path is worth 15 m / s, instead the vertical speed changes in value due to the acceleration of gravity, let's look for the initial vertical speed

                      Vy² =v_{oy}² - 2 g y

                      v_{oy}² = v_{y}² + 2 g y

                       v_{oy} = √ (v_{y}² + 2 gy

Let's calculate

                    v_{oy} = √ (1.25² + 2 9.8 1.3)

                    v_{oy} = √ (27.04)

                    v_{oy} = 5.2 m / s

 The initial speed can be calculated by the initial speed

                   v = √ v₀ₓ² + v_{oy}²

                   v = RA (15² + 5.2²)

                   v = 15.87 m / s

We look for the angle with trigonometry

                 tan θ = voy / vox

                 θ = tan⁻¹ I'm going / vox

                θ = tan⁻¹ 5.2 / 15

                θ = 19.1

The answer is

              v₀ₓ = 15 m / s

              v_{oy} = 5.2 m / s

5 0
1 year ago
The distance of the earth from the sun is 93 000 000 miles. if there are 3.15 × 107 s in one year, find the speed of the earth i
faltersainse [42]

The angular velocity of the orbit about the sun is:

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Now in 1 rev there is 360° or 2π rad, therefore:

w = 2π rad / 3.15 × 10^7 s

 

To convert in linear velocity, multiply the rad /s by the radius:

v = (2π rad / 3.15 × 10^7 s) * 93,000,000 miles

<span>v = 18.55 miles / s = 29.85 km / s</span>

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2 years ago
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Ludmilka [50]
The correct answer would be B. It is the compound Na2S that forms an ionic bond from the given ion above. From the choices, it is the only compound that exist and is available. Metals cannot react with another metal as well as nonmetal to nonmetal. 
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2 years ago
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