1) weight of the box: 980 N
The weight of the box is given by:
where m=100.0 kg is the mass of the box, and 
is the acceleration due to gravity. Substituting in the formula, we find
2) Normal force: 630 N
The magnitude of the normal force is equal to the component of the weight which is perpendicular to the ramp, which is given by
where W is the weight of the box, calculated in the previous step, and 
is the angle of the ramp. Substituting, we find
3) Acceleration: 
The acceleration of the box along the ramp is equal to the component of the acceleration of gravity parallel to the ramp, which is given by
Substituting, we find
B. velocity at position x, velocity at position x=0, position x, and the original position
In the equation
= 
+2 a x (x - x₀)
= velocity at position "x"
= velocity at position "x = 0 "
x = final position
= initial position of the object at the start of the motion
Answer:
v = 36.667 m/s
Explanation:
Knowing the rotational inertia as
Lₙ = 550 kg * m²
r = 1.0 m
m = 30.0 kg
To determine the minimum speed v must have when she grabs the bottom
Lₙ = I * ω
I = ¹/₂ * m * r²
I = ¹/₂ * 30.0 kg * 1.0² m
I = 15 kg * m²
Lₙ = I * ω ⇒ ω = Lₙ / I
ω = [ 550 kg * m² /s ] / ( 15 kg * m² )
ω = 36.667 rad /s
v = ω * r
v = 36.667 m/s
Answer:
at the highest point of the path the acceleration of ball is same as acceleration due to gravity
Explanation:
At the highest point of the path of the ball the speed of the ball becomes zero as the acceleration due to gravity will decelerate the motion of ball due to which the speed of ball will keep on decreasing and finally it comes to rest
So here we will say that at the highest point of the path the speed of the ball comes to zero
now by the force diagram we can say that net force on the ball due to gravity is given by
now the acceleration of ball is given as
so at the highest point of the path the acceleration of ball is same as acceleration due to gravity
Here in this question as we can see there is no air friction so we can use the principle of energy conservation
now here we know that
now plug in all values in above equation
divide whole equation by mass "m"
so height of the ball from ground will be 1.35 m
