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stich3 [128]
2 years ago
5

Find the lowest two frequencies that produce a maximum sound intensity at the positions of Moe and Curly.

Physics
1 answer:
Mars2501 [29]2 years ago
7 0

Answer:

hello your question has some missing parts below is the complete question

and the missing diagram

The two speakers emit sound that is 180° out of phase and of a single frequency,ƒ, Find the lowest two frequencies that produce a maximum sound intensity at the positions of Moe and Curly.

answer : 1316.2 hertz

Explanation:

The frequency that produce the maximum sound intensity can be calculated using the relation below

dsin ∅ = n <em>A</em>

where <em>A = </em>dsin ∅ / n  when n = 1 . d = 0.800

<em>A</em> = 0.800 * ( 1 / 3.162 )

<em>A</em> = 0.253 m

speed of sound = 333 m/s

frequency = speed /<em> A</em>

<em>=   </em>333 / 0.253 =  1316.2 hertz

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A man walks 30 m to the west, then 5 to the east in 45 seconds
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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 4.00. What should be the length of B⃗ so that th
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A uniform rectangular plate is hanging vertically downward from a hinge that passes along its left edge. By blowing air at 11.0
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Answer:

The airspeed must be 7.78 m/s for the rectangular plate kept at 30°.

Explanation:

By looking at the images below wee see that the airspeed on one side of the rectangular plate decreases the statical pressure over this side. Since over the downside, the pressure still bein the atmospheric pressure. This difference in pressure produces a lift force in the plate. The list force is the net force obtained between the difference of the forces that produce the pressure over the upside and the downside:

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When the plate kept to 30° from the vertical the moment equation balance is written as:

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V=\sqrt(W*sen(30\°)/0.5p)

V=\sqrt(\frac{72.6 N * 0.5}{0.5*1.2 kg/m^3})

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V=\sqrt(60.5 \frac{kg.m/s^2}{kg/m^3})

V=\sqrt(60.5 \frac{m^2}{s^2})

V= 7.78 m/s

7 0
2 years ago
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