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dalvyx [7]
2 years ago
6

Consider three identical metal spheres, A, B, and C. Sphere A carries a charge of -2.0 µC; sphere B carries a charge of -6.0 µC;

and sphere C carries a charge of +4.0 µC. Spheres A and B are touched together and then separated. SpheresB and C are then touched and separated. Does sphere C end up with an excess or a deficiency of electrons and how many electrons is it?Select one:A. deficiency, 6 × 10^13B. excess, 2 × 10^13C. There is no excess or deficiency of electrons.D. excess, 3 × 10^13E. deficiency, 3 × 10^12
Physics
1 answer:
Dmitry_Shevchenko [17]2 years ago
5 0

Answer:

None of the option is correct

A=-4µC, B=0 C, C=0 C

C will be +4.0 µC deficient after the contact

Explanation:

A and B are come in contact together, the charge will flow to establish  equilibrium, and hence becoming: A=-4µC, B=-4µC, C=+4.0 µC

Similarly when C and B touch, the positive and the negative will exact the same force due to equal charge magnitude and become electrically neutral : A=-4µC, B=0 C, C=0 C.

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The magnetic field of an electromagnetic wave in a vacuum is Bz =(2.4μT)sin((1.05×107)x−ωt), where x is in m and t is in s. You
tatiyna

Answer:

Explanation:

Given

B_z=(2.4\mu T)\sin (1.05\times 10^7x-\omega t)

Em wave is in the form of

B=B_0\sin (kx-\omega t)

where \omega =frequency\ of\ oscillation

k=wave\ constant

B_0=Maximum\ value\ of\ Magnetic\ Field

Wave constant for EM wave k is

k=1.05\times 10^7 m^{-1}

Wavelength of wave \lambda =\frac{2\pi }{k}

\lambda =\frac{2\pi }{1.05\times 10^7}

\lambda =5.98\times 10^{-7} m

7 0
2 years ago
In a car crash, large accelerations of the head can lead to severe injuries or even death. A driver can probably survive an acce
noname [10]

Answer:

14.7 m/s

Explanation:

a = acceleration experienced by driver's head = 50 g = 50 x 9.8 m/s² = 490 m/s²

v₀ = initial speed of the driver = 0 m/s

v = final speed of the driver after 30 ms

t = time interval for which the acceleration is experienced = 30 ms = 0.030 s

Using the equation

v = v₀ + a t

Inserting the values

v = 0 + (490) (0.030)

v = 14.7 m/s

6 0
2 years ago
An electric heater draws a steady current = 20.0 A on a 120-V line. (a) Calculate how much power does it require.
babymother [125]

Answer:

The heater power required is 2400 W. The power in the heater can be calculated as the product of the voltage line and the steady current:

P=V.I

P=120 V * 20 A = 2400 VA = 2400 W

Explanation:

8 0
2 years ago
The mass per unit length of a 14-gauge copper wire is 18.5 g/m. If the wire is placed running along the horizontal x-axis (east-
zmey [24]

Answer:

0.6295 A

Explanation:

I=mg/BL put values in this formula.  

7 0
1 year ago
An object has a position given by r = [2.0 m + (2.00 m/s)t] i + [3.0 m − (1.00 m/s^2)t^2] j, where quantities are in SI units. W
lidiya [134]

Answer: 1 m/s

Explanation:

We have an object whose position r is given by a vector, where the components X and Y are identified by the unit vectors i and j (where each unit vector is defined to have a magnitude of exactly one):

r=[2 m + (2 m/s) t] i + [3 m - (1 m/s^{2})t^{2}] j

On the other hand, velocity is defined as the variation of the position in time:

V=\frac{dr}{dt}

This means we have to derive r:

\frac{dr}{dt}=\frac{d}{dt}[2 m + (2 m/s) t] i + \frac{d}{dt}[3 m - (1 m/s^{2})t^{2}] j

\frac{dr}{dt}=(2 m/s) i - (\frac{1}{2} m/s^{2} t) j This is the velocity vector

And when t=2s the velocity vector is:

\frac{dr}{dt}=(2 m/s) i - (\frac{1}{2} m/s^{2} (2 s)) j

\frac{dr}{dt}=2 m/s i - 1m/s j This is the velocity vector at 2 seconds

However, the solution is not complete yet, we have to find the module of this velocity vector, which is the speed S:

S=\sqrt {-1 m/s j + 2 m/s i}

S=\sqrt {1 m/s}

Finally:

S=1 m/s This is the speed of the object at 2 seconds

6 0
1 year ago
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