Answer:
Explanation:
= 250 moles.
N = n×6.02×
= 1.505×
Total charge = (1.505×) × (1.6×
)
= 2.4× C.
If Anya decides to make the star twice as massive, and not change the length of any crossbar or the location of any object, what
1 answer:
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Answer:
(C) 4 beats per second.
Explanation:
As we know that the no of beats can be calculated as.
No. of beats is equal to difference in the tuning forks frequencies.
So,
.
Substitute the values of frequencies of 2 tuning forks in the above equation.
Therefore the number of beats per second will be hear by the observer is 4 beats per second.
Answer:
10.791 m/s
5.93505 m
Explanation:
m = Mass of ball
= Final velocity
= Initial velocity
= Final time
= Initial time
g = Acceleration due to gravity = 9.81 m/s²
From the momentum principle we have
Force
So,
The speed that the ball had just after it left the hand is 10.791 m/s
As the energy of the system is conserved
The maximum height above your hand reached by the ball is 5.93505 m
Answer:
v₂ = v/1.5= 0.667 v
Explanation:
For this exercise we will use the conservation of the moment, for this we will define a system formed by the two students and the cars, for this isolated system the forces during the contact are internal, therefore the moment conserves.
Initial moment before pushing
p₀ = 0
Final moment after they have been pushed
= m₁ v₁ + m₂ v₂
p₀ =
0 = m₁ v₁ + m₂ v₂
m₁ v₁ = - m₂ v₂
Let's replace
M (-v) = -1.5M v₂
v₂ = v / 1.5
v₂ = 0.667 v