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2 years ago

A cheetah can run at 30 m/s, but only for about 12s. How far will it run in that time

Physics

1 answer:

Alexxx [7]2 years ago

7 0

A cheetah can run at 30 m/s, but only for about 12s. How far will it run in that time12x30=360 miles

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Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so

lisabon 2012 [21]

As per kinematics equation we are given that

$v^2 = v_o^2 + 2ax$

now we are given that

a = 2.55 m/s^2

$v_0 = 21.8 m/s$

$v = 0$

now we need to find x

from above equation we have

$0^2 = 21.8^2 + 2(2.55)x$

$0 = 475.24 + 5.1 x$

$x = 93.2 m$

so it will cover a distance of 93.2 m

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2 years ago

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An electric dipole with dipole moment p⃗ is in a uniform electric field E⃗ . A. Find all the orientation angles of the dipole me

Tasya [4]

Answer:

Explanation:

A) When a dipole is placed in an electric field , it experiences a torque equal to the following

torque = p x E = p E sinθ , where θ is angle between direction of p and E .

It will be zero if θ = 0

or if both p and E are oriented in the same direction.

It is the stable orientation of dipole.

If θ = 180° ,

Torque = 0

In this case both p and E are oriented in opposite direction .

It is the unstable orientation of the dipole because if we deflect the dipole by even small angle , it goes back to most stable orientation due to torque acting on it by electric field.

3 0

2 years ago

Monitoring systems may also use ____, which are devices that respond to a stimulus (such as heat, light, or pressure) and genera

KIM [24]

The answer is:
__________________________________________________
"sensors"
__________________________________________________
"<span>Monitoring systems may also use ___<u>sensors</u>___, which are devices that respond to a stimulus (such as heat, light, or pressure) and generate an electrical signal that can be measured or interpreted."
_________________________________________________</span>

6 0

2 years ago

(II) A sled is initially given a shove up a frictionless 23.0° incline. It reaches a maximum vertical height 1.22 m higher than

vodka [1.7K]

Answer:

4.88 m/s

Explanation:

Using the law of conservation of energy, we know that energy can neither be created nor destroyed but can only be transformed from one state to another. Therefore, the kinetic energy at the inclined bottom equals to the potential energy at the top hence $0.5mv^{2}=mgh$

and making v the subject of the formula then $v=2gh$ where m represnt the mass of sled, v is the initial speed, g is acceleration due to gravity and h ia the vertical height. Substituting g with 9.81 m/s2 and h with 1.22 then

$v=2\times 9.81\times 1.22\approx 4.88 m/s$

5 0

2 years ago

A particle's position as a function of time t is given by r⃗ =(5.0t+6.0t2)mi^+(7.0−3.0t3)mj^.

nalin [4]

The given particle position is
$\vec{r}(t)=(5.0t+6.0t^{2})\hat{i}+(7.0-3.0t^{3})\hat{j}$

When t=5 s, the position vector is
$\vec{r}_{1} = (5+150)\hat{i}+(7-375)\hat{j} = 175\hat{i}-368\hat{j}$

The reference vector at t = 5 s is
$\vec{r}_(2) = 0\hat{i}+7\hat{j}.$

Let θ = the angle between the two vectors.
Then, by definition,
$\vec{r}_{1}.\vec{r}_{2}=|r_{1}||r_{2}|cos\theta$

|r₁} = √[175²+(-368)²] = 407.4911
|r₂| = 7
$\vec{r}_{1}.\vec{r}_{2}=(-368)*(7) = -2576$

Therefore
θ = cos⁻¹ -2576/(407.4911*7) = cos⁻¹ -0.9031 = 154.57°

Answer: 154.57°

3 0

2 years ago

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