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Leona [35]
1 year ago
12

A cheetah can run at 30 m/s, but only for about 12s. How far will it run in that time

Physics
1 answer:
Alexxx [7]1 year ago
7 0

A cheetah can run at 30 m/s, but only for about 12s. How far will it run in that time12x30=360 miles 
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Explain how scientists know that elephants and hyraxes are related. Be sure to include anatomical similarities as well as fossil
leonid [27]

<em>Hyraxes, elephants and dugongs are more closely related to one another than to any other living animal.  Well, that's not exactly true. The closest surviving relative of the dugong is the manatee, a fresh-water, New-World version of itself. Apart from this, and the fact that there are two species of elephant and several of hyrax, it's absolutely true. Hyraxes, elephants and dugongs evolved from a single common ancestor.</em>

                                          Hope This Helps

8 0
1 year ago
Read 2 more answers
Apollo 14 astronaut Alan B. Shepard Jr. used an improvised six-iron to strike two golf balls while on the Fra Mauro region of th
Citrus2011 [14]

Answer:

(a) Rm = 268.4 m

(b) f = 6

Explanation:

The horizontal range of a projectile is given by the following formula:

R = V₀² Sin 2θ/g

(a)

For moon:

R = Range on moon = Rm

V₀ = Launch Speed = 28 m/s

θ = Launch Angle = 17°

g = acceleration due to gravity on moon = (9.8 m/s²)/6 = 1.63 m/s²

Therefore,

Rm = (28 m/s)²Sin (2*17°)/(1.63 m/s²)

<u>Rm = 268.4 m</u>

(b)

For Earth:

R = Range on Earth = Re

V₀ = Launch Speed = 28 m/s

θ = Launch Angle = 17°

g = acceleration due to gravity on Earth = 9.8 m/s²

Therefore,

Re = (28 m/s)²Sin (2*17°)/(9.8 m/s²)

Re = 44.7 m

Therefore.

f = Rm/Re = 268.4 m/44.7 m

<u>f = 6</u>

3 0
1 year ago
A submarine periscope uses two totally reflecting 45-45-90 prisms with total internal reflection on the sides adjacent to the 45
Likurg_2 [28]

Answer

Given,

Periscope uses 45-45-90 prisms with total internal reflection adjacent to 45°.

refractive index of water, n_a = 1.33

refractive index of glass, n_g = 1.52

When the light enters the water, water will act as a lens and when we see the object from the periscope the object shown is farther than the usual distance.

7 0
1 year ago
A child is sliding a toy block (with mass = m) down a ramp. The coefficient of static friction between the block and the ramp is
tiny-mole [99]

Answer:

F=mg(sin(\theta )-0.25 cos(\theta ))

Explanation:

The free body diagram of the block on the slide is shown in the below figure

Since the block is in equilibrium we apply equations of statics to compute the necessary unknown forces

N is the reaction force between the block and the slide

For equilibrium along x-axis we have

\sum F_{x}=0\\\\mgsin(\theta )-\mu N-F=0\\\therefore F=mgsin(\theta)-\mu N......(\alpha )\\Similarly\\\sum F_{y}=0\\\\N-mgcos(\theta )=0\\\therefore N=mgcos(\theta ).......(\beta )\\\\

Using value of N from equation β in α we get value of force as

F=mg(sin(\theta )-\mu cos(\theta ))

Applying values we get

F=mg(sin(\theta )-0.25 cos(\theta ))

8 0
1 year ago
Read 2 more answers
A professor's office door is 0.99 m wide, 2.2 m high, 4.2 cm thick; has a mass of 27 kg, and pivots on frictionless hinges. A "d
ANEK [815]

Answer:

I=8.8209\ kg.m^2

\alpha=0.6348\ rad.s^{-2}

Explanation:

Given:

  • width of door, w=0.99\ m
  • height of the door, h=2.2\ m
  • thickness of the door, t=4.2\ cm
  • mass of the door, m=27\ kg
  • torque on the door, \tau=5.6\ N.m

<em>∵Since the thickness of the door is very less as compared to its other dimensions, therefore we treat it as a rectangular sheet.</em>

  • For a rectangular sheet we have the mass moment of inertia inertia as:

I=\frac{1}{3} m.w^2

I=\frac{1}{3}\times 27\times 0.99^2

I=8.8209\ kg.m^2

We have a relation between mass moment of inertia, torque and angular acceleration as:

\alpha=\frac{\tau}{I}

\alpha=\frac{5.6}{8.8209}

\alpha=0.6348\ rad.s^{-2}

6 0
1 year ago
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