answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zavuch27 [327]
2 years ago
10

A proton and an electron are held in place on the x axis. The proton is at x = -d, while the electron is at x = +d. They are rel

eased simultaneously, and the only force that affects their motions is the electrostatic force of attraction that applies to the other. Which particle reaches the origin first? Give your reasoning.
Physics
1 answer:
Over [174]2 years ago
6 0
The protons and electrons are held in place on the x axis.
The proton is at x = -d and the electron is at x = +d. They are released at the same time and the only force that affects movement is the electrostatic force that is applied on both subatomic particles. According to Newton's third law, the force Fpe exerted on protons by the electron is opposite in magnitude and direction to the force Fep exerted on the electron by the proton. That is, Fpe = - Fep. According to Newton's second law, this equation can be written as
                               Mp * ap = -Me * ae
where Mp and Me are the masses, and ap and ae are the accelerations of the proton and the electron, respectively. Since the mass of the electron is much smaller than the mass of the proton, in order for the equation above to hold, the acceleration of the electron at that moment must be considerably larger than the acceleration of the proton at that moment. Since electrons have much greater acceleration than protons, they achieve a faster rate than protons and therefore first reach the origin.
You might be interested in
A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. immediat
koban [17]
<span>We'll use the momentum-impulse theorem. The x-component of the total momentum in that direction is given by p_(f) = p_(1) + p_(2) + p_(3) = 0.
  So p_(1x) = m1v1 = 0.2 * 2 = 0.4 Also p_(2x) = m2v2 = 0 and p_(3x) = m3v3 = 0.1 *v3 where v3 is unknown speed and m3 is the mass of the third particle with the unknown speed
 Similarly, the 235g particle, y-component of the total momentum in that direction is given by p_(fy) = p_(1y) + p_(2y) + p_(3y) = 0.
 So p_(1y) = 0, p_(2y) = m2v2 = 0.235 * 1.5 = 0.3525 and p_(3y) = m3v3 = 0.1 * v3 where m3 is third particle mass.
  So p_(fx) = p_(1x) + p_(2x) + p_(3x) = 0.4 + 0.1v3; v3 = 0.4/-0.1 = - 4
 Also p_(fy) = 0.3525 + 0.1v3; v3 = - 0.3525/0.1 = -3.525
  So v_3x = -4 and v_3y = 3.525.
 The speed is their resultant = âš (-4)^2 + (-3.525)^2 = 5.335</span>
4 0
1 year ago
Read 2 more answers
The particle starts from rest at t=0. What is the magnitude p of the momentum of the particle at time t? Assume that t&gt;0. Exp
olganol [36]

Answer:

Ft

Explanation:

We are given that

Initial velocity=u=0

We have to find the magnitude of p of the momentum of the particle at time t.

Let mass of particle=m

Applied force=F

Acceleration, a=\frac{F}{m}

Final velocity , v=a+ut

Substitute the values

v=0+\frac{F}{m}t=\frac{F}{m}t

We know that

Momentum, p=mv

Using the formula

p=m\times \frac{F}{m}t=Ft

6 0
2 years ago
The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an
Troyanec [42]

Answer:

3400 Hz

Explanation:

We know that

1 cm = 0.01 m

L = Length of the human ear canal = 2.5 cm = 0.025 m

V = Speed of sound = 340 ms⁻¹

f = First resonant frequency

The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

f = \frac{(2n - 1)V}{4L}

for first resonant frequency, we have n = 1

Inserting the values

f = \frac{(2(1) - 1) 340}{4(0.025)}

f = \frac{340}{4(0.025)}

f = 3400 Hz

4 0
2 years ago
Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. Part A If the surfac
alukav5142 [94]

Answer:

5308.34 N/C

Explanation:

Given:

Surface density of each plate (σ) = 47.0 nC/m² = 47\times 10^{-9}\ C/m^2

Separation between the plates (d) = 2.20 cm

We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

E=\dfrac{\sigma}{2\epsilon_0}

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

E_{between}=E+E=2E=\frac{2\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}

Now, plug in  47\times 10^{-9}\ C/m^2 for 'σ' and 8.85\times 10^{-12}\ F/m for \epsilon_0 and solve for the electric field. This gives,

E_{between}=\frac{47\times 10^{-9}\ C/m^2}{8.854\times 10^{-12}\ F/m}\\\\E_{between}= 5308.34\ N/C

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C

5 0
1 year ago
A child’s toy rake is held so that its resistance length is 0.85 meters. If the mechanical advantage is 0.43, what is the effort
mart [117]

Answer:

1.28

Explanation:

7 0
1 year ago
Other questions:
  • A satellite orbiting above the earth needs no power source to keep orbiting the earth. The best explanation for this involves th
    11·2 answers
  • Not too long ago houses were protected from excessive currents by fuses rather than circuit breakers. sometimes a fuse blew out
    9·1 answer
  • The helicopter in the drawing is moving horizontally to the right at a constant velocity. The weight of the helicopter is W=4900
    5·1 answer
  • What is the effect of the following change on the volume of 1 mol of an ideal gas? The initial pressure is 722 torr, the final p
    13·1 answer
  • Calculate the time taken by the light to pass through a nucleus of diameter 1.56 10 -16 m. (speed of light is 3 10 8 m/s)
    10·1 answer
  • In a pith ball experiment, the two pith balls are at rest. The magnitude of the tension in each string is |T|=0.55N, and the ang
    8·1 answer
  • Calculate the percent error of the distance to the moon.
    13·1 answer
  • A rod 16.0 cm long is uniformly charged and has a total charge of -25.0 µC. Determine the magnitude and direction of the electri
    9·1 answer
  • Q1: An object with a charge of 1.2 C is located 4.5 m away from a second object that has a charge of 0.36 C. Find the electrical
    6·1 answer
  • A certain force gives object m1 an acceleration of 12.0 m/s2. The same force gives object m2 an acceleration of 3.30 m/s2. What
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!