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Tpy6a [65]
2 years ago
14

Liz puts a 1 kg weight and a 10 kg on identical sleds. She then applies a 10N force to each sled. Describe why the smaller weigh

t has a larger acceleration. A) There is same amount force is applied to both sleds. B) The acceleration is directly proportional to the force. C) It indicates the extent of the unbalanced forces present. D) Acceleration depends indirectly on the mass of the object.
Physics
2 answers:
elena-14-01-66 [18.8K]2 years ago
8 0

the correct answer is D- Acceleration depends indirectly on the mass.

According to Newton's second law, the force F, the mass m and the acceleration a are related as follows:

F=ma

Therefore,

a=\frac{F}{m}

The acceleration <em>a₁ </em>of the mass<em> m₁ =1 kg</em>  is given by,

a_1=\frac{F}{m_1} \\ =\frac{10N}{1kg} \\ =10m/s^2

The acceleration <em>a₂ </em>of the mass <em>m₂=10 kg</em> is given by,

a_2=\frac{10N}{10kg} \\ =1m/s^2

The smaller mass has greater acceleration.

Thus, when the force applied on two bodies of different masses remains constant, then,

a\alpha  \frac{1}{m}

Acceleration is inversely proportional to the mass of the body.



laiz [17]2 years ago
8 0

the answer is D i had the test

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If a sound with frequency fs is produced by a source traveling along a line with speed vs. If an observer is traveling with spee
Alexus [3.1K]

Answer:

457.81 Hz

Explanation:

From the question, it is stated that it is a question under Doppler effect.

As a result, we use this form

fo = (c + vo) / (c - vs) × fs

fo = observed frequency by observer =?

c = speed of sound = 332 m/s

vo = velocity of observer relative to source = 45 m/s

vs = velocity of source relative to observer = - 46 m/s ( it is taking a negative sign because the velocity of the source is in opposite direction to the observer).

fs = frequency of sound wave by source = 459 Hz

By substituting the the values to the equation, we have

fo = (332 + 45) / (332 - (-46)) × 459

fo = (377/ 332 + 46) × 459

fo = (377/ 378) × 459

fo = 0.9974 × 459

fo = 457.81 Hz

7 0
2 years ago
Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the en
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<span>If the maximum permissible limit for depression of the structure is 20 centimeters, the number of floors that can be safely added to the building is </span><span>C. 18</span>

depression = (depression/floor)(# floors) < 20

Here are the following choices:
<span>A. 14
B. 15
C. 18
D. 23</span>
8 0
1 year ago
Which of the following sketches represents a possible configuration for this problem?
garri49 [273]
Where are the following sketches?
7 0
2 years ago
If a young protostar with a disk is rotating and shrinking. how much faster is it rotating after its size has decreased by a fac
maks197457 [2]
In this system we have the conservation of angular momentum: L₁ = L₂
We can write L = m·r²·ω

Therefore, we will have:
m₁ · r₁² · ω₁ = m₂ · r₂² · ω₂

The mass stays constant, therefore it cancels out, and we can solve for ω<span>₂:
</span>ω₂ =  (r₁/ r₂)² · ω<span>₁
     
Since we know that r</span>₁ = 4r<span>₂, we get:
</span>ω₂ =  (4)² · ω<span>₁
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Hence, the protostar will be rotating 16 </span><span>times faster.</span>
5 0
2 years ago
The deuterium nucleus starts out with a kinetic energy of 1.24 × 10-13 joules, and the proton starts out with a kinetic energy o
MrMuchimi

Answer:

The total kinetic energy of both particles is 2.43\times10^{-13}

Explanation:

Given that,

Kinetic energy of nucleusK.E= 1.24\times10^{-13}\ J

Kinetic energy of proton K.E= 2.47\times10^{-13}\ J

Radius of proton r= 0.9\times10^{-15}\ m

We need to calculate the final potential energy

Using formula of final potential energy

U=\dfrac{kq^2}{r}

Put the value into the formula

U_{f}=\dfrac{9\times10^{9}\times(1.6\times10^{-19})^2}{2\times0.9\times10^{-15}}

U_{f}=1.28\times10^{-13}\ J

We need to calculate the initial energy of both the particles

Using formula of energy

E_{i}=(K.E_{n}+K.E_{p})+U_{i}

E_{i}=1.24\times10^{-13}+2.47\times10^{-13}+0

E_{i}=3.71\times10^{-13}\ J

We need to calculate the total kinetic energy of both particles

Using conservation of energy

E_{i}=E_{f}

E_{i}=K.E_{f}+U_{f}

3.71\times10^{-13}=K.E_{f}+1.28\times10^{-13}

K.E_{f}=3.71\times10^{-13}-1.28\times10^{-13}

K.E_{f}=2.43\times10^{-13}

Hence, The total kinetic energy of both particles is 2.43\times10^{-13}

3 0
1 year ago
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