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sladkih [1.3K]
2 years ago
14

Two students push a heavy crate across the floor. John pushes with a force of 185 N due east and Joan pushes with a force of 165

N at 30∘north of east. What is the resultant horizontal force on the crate?

Physics
1 answer:
zubka84 [21]2 years ago
3 0

Answer:

327.894 N

Explanation:

We have given two forces Jhon pushes with a force of 185 N in east direction and Joan pushes with a force of 165 N at 30° north of east which is clearly shown in figure

We fave to find the total horizontal force

So total horizontal force will be F_X=185+165cos30^{\circ} =327.894 N ( total horizontal force will be sum of force in the east direction and horizontal component of the force in north- east direction)

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cluponka [151]

Answer:

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Explanation:

This is a vector exercise, the best way to solve it is finding the components of each vector and doing the addition

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let's use trigonometry to find its components

         cos 45 = x₁ / V₁

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         x₁ = 26 cos 45

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Unknown 3 vector

          x3 =?

          y3 =?

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we make the sum on each axis

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       x₃ = 0 - 18.38

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Y Axis

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the vector of the third leg of the journey is

         v₃ = (-18.38 i ^ +6.62 j^ ) km

let's use the Pythagorean theorem to find the length

         v₃ = √ (18.38² + 6.62²)

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           tan θ = y₃ / x₃

           θ = tan⁻¹ (y₃ / x₃)

           θ = tan⁻¹ (6.62 / (- 18.38))

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with respect to the x axis, if we measure this angle from the positive side of the x axis it is

          θ’= 180 -19.8

          θ’= 160.19º

I mean the address is

          θ’’ = 90-19.8

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Answer:

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2 years ago
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