Two students push a heavy crate across the floor. John pushes with a force of 185 N due east and Joan pushes with a force of 165
N at 30∘north of east. What is the resultant horizontal force on the crate?
1 answer:
Answer:
327.894 N
Explanation:
We have given two forces Jhon pushes with a force of 185 N in east direction and Joan pushes with a force of 165 N at 30° north of east which is clearly shown in figure
We fave to find the total horizontal force
So total horizontal force will be =327.894 N ( total horizontal force will be sum of force in the east direction and horizontal component of the force in north- east direction)
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Answer:
The frequency is
Explanation:
From the question we are told that
The third harmonic frequency of the tight guitar string is
Let the original length be L
Then the length at which it is fingered is 0.7 L
Generally the fundamental is mathematically represented as
Now when it finger at 70% it original length is
Here v the velocity of sound
So
Also the fundamental frequency for the original length can also be represented as
substituting values
So
=>
=>
The acceleration of the ball in the vertical direction is , downward.
Explanation:
This is a typical example of projectile motion, which consists of two independent motions:
- A uniform horizontal motion at constant velocity (since there are no forces in the horizontal direction)
- A vertical accelerated motion at constant acceleration (due to the presence of the force of gravity)
We are considering now the vertical motion only. There is only one force acting on the ball in this direction: the force of gravity, of magnitude
F = mg
where m is the mass of the ball and the acceleration due to gravity, downward. This means that the acceleration of the ball in this direction is (using Newton's second law)
Therefore, the acceleration of the ball in the vertical direction is , downward.
Learn more about projectile motion:
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