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Murrr4er [49]
2 years ago
9

A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0.2 kg, and the robo

t has a mass of 0.5 kg. The robot pushes on the doll with a force of 1 N. The magnitude of the acceleration of the robot is
Physics
1 answer:
Natali5045456 [20]2 years ago
3 0

Answer:

<h3>1.43m/s²</h3>

Explanation:

According to newtons second law.

F = mass * acceleration

If the doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg, the resulting mass will be 0.7kg

Force applied = 1N

acceleration = Force/mass

Substitute the values and get acceleration

acceleration = 1/0.7

acceleration = 1.43m/s²

Hence the magnitude of the acceleration of the robot is 1.43m/s²

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What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at
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Answer:

m = 0.111 kg

Explanation:

Heat required to release from the body of the person when his temperature cool down by 1 degree C is given as

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here we know that

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2 years ago
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Artyom0805 [142]

Answer:

75 m

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Density is mass divides by volume, so
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your drop a coin from the top of a hundred-story building(1000m). If you ignore air resistance, how fast will it be falling righ
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consider the motion of con from top to bottom

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v = 140 m/s


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Using the equation

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