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2 years ago

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A substance has a specific heat of 0.870 J/g°C. It requires 2,000.0 joules to increase the temperature of 10.0 grams of the subs

tance from its original temperature to its final temperature.
By how many degrees did the substance increase?
87.0°C
174°C
230°C
1,740°C

2 answers:

Archy [21]2 years ago

7 0

Cccccccccccccccccc....................

xz_007 [3.2K]2 years ago

4 0

Answer: $230^0C$

Explanation:

$Q=m\times c\times \Delta T$

q = heat absorbed or released by a substance = 2000.0 J

m= Mass of substance = 10.0 g

c = specific heat of the substance = $0.870 J/g^0C$

$\Delta T=T_f-T_i$ = Change in temperature

Putting in the values we get:

$2000.0J=10.0g\times 0.870J/g^0C\times \Delta T$

$\Delta T=230^0C$

Thus the temperature changed by $230^0C$ .

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