Question

A substance has a specific heat of 0.870 J/g°C. It requires 2,000.0 joules to increase the temperature of 10.0 grams of the substance from its original temperature to its final temperature.
By how many degrees did the substance increase?
87.0°C
174°C
230°C
1,740°C

Answer 1

Cccccccccccccccccc....................

Answer 2

Answer: $230^0C$

Explanation:

$Q=m\times c\times \Delta T$

q = heat absorbed or released by a substance = 2000.0 J

m= Mass of substance = 10.0 g

c = specific heat of the substance = $0.870 J/g^0C$

$\Delta T=T_f-T_i$ = Change in temperature

Putting in the values we get:

$2000.0J=10.0g\times 0.870J/g^0C\times \Delta T$

$\Delta T=230^0C$

Thus the temperature changed by $230^0C$.