Question

A soap bubble has a diameter of 4mm .Cakculate the pressure inside it if the atmospheric pressure outside is 10^5Nm^2 . The surface tension of soap =2.8* 10^-2N/m

Answer 1

Answer:

Explanation:

The formula for determining the pressure inside a soap bubble is expressed as

Pi - Po = 4T/r

Where

Pi represents the pressure inside the bubble.

Po represents the pressure outside the bubble or the atmospheric pressure.

T represents the surface tension.

r represents radius of the bubble.

From the information given,

Diameter of bubble = 4mm. Converting to meters, it becomes

4/1000 = 0.004m

Radius of bubble = 0.004/2 = 0.002m

T = 2.8 × 10^-2N/m

Po = 1 × 10^5Nm^-2

Therefore,

Pi - 10^5 = 4 × 2.8 × 10^ -2/0.004

Pi - 10^5 = 28

Pi = 28 + 1 × 10^5 = 100028Nm^-2

Answer 2

Look it up it will give the right anwser