Question

A person is pushing a fully loaded 21.60 kg wheelbarrow at constant velocity along a plank that makes an angle ????=20.0∘ with the horizontal. The load is distributed such that the center of mass of the wheelbarrow is exactly halfway along its length L. What is the magnitude of the total force Fx the person must apply so that the wheelbarrow is parallel to that plank? You may neglect the radius of the wheel in your analysis. The gravitational acceleration is g=9.81 m/s2.

Answer 1

Answer:

Explanation:

The weight of the wheelbarrow will act downwards . Its component parallel to the plank will act downwards along the plank .

The value of component = mgsinθ

21.6 x 9.8 x sin20

= 72.4 N

The person shall have to apply force equal to this component so that the barrow moves with uniform velocity.

Force required = 72.4 N .