Ask question

Ask question

All categories

2 years ago

5

The magnitude of the electrical force acting between a +2.4 × 10–8 C charge and a +1.8 × 10–6 C charge that are separated by 0.0

08 m is N, rounded to the tenths place.

2 answers:

solong [7]2 years ago

8 0

To answer this question, we will simply use Coulomb's which is stated as follows:
F = k*q1*q2 / r^2 where:
F is the magnitude of the force between the two charges
k is a constant = 9.00 * 10^9 N.m^2/C^2
q1 = <span>+2.4 × 10–8 C
q2 = </span><span>+1.8 × 10–6 C
r is the distance between the two charges = </span><span>0.008 m

Substituting in the equation, we get:
F = (9*10^9)(2.4*10^-8)(1.8*10^-6) / (0.008)^2 = 6.075 which is approximately 6.1 Newtons

</span>

brilliants [131]2 years ago

8 0

On Ed. its 6.1 N. Just took the test and got it right soooo.

You might be interested in

Consider an alcohol and a mercury thermometer that read exactly 0 oC at the ice point and 100 oC at the steam point. The distanc

Alexeev081 [22]

Answer:

No, both the thermometers will give the different reading.

Explanation:

Given,

Both thermometer has same ice point = $T_i\ =\ 0^o C$
Both thermometer has same steam point = $T_s\ =\ 100^o C$

Distance between the ice point and steam point in both the thermometer is same of 100 division,

All the data given in both the thermometers are same, but the material in the thermometer is different due to this the reading at 60^o C will differ in both the thermometer. Because the reading on both the thermometer is depended upon the thermal expansion of the material inside it, but both the materials are different. Due to this the rise of fluid in the thermometer, i,e,. the volume of the fluid material in the thermometer will depend upon the thermal expansion. Hence both the material alcohol and mercury have the different thermal expansion, therefore the rise of the fluid in the thermometer also differ in both the thermometer.

7 0

2 years ago

A wave has a frequency of 15,500 Hz and a wavelength of 0.20 m. What is the

Hoochie [10]

Answer:

3100 m/s

Explanation:

The relationship between frequency and wavelength of a wave is given by the wave equation:

$v=f\lambda$

where

v is the speed of the wave

f is its frequency

$\lambda$ is the wavelength

For the wave in this problem,

f = 15,500 Hz

$\lambda=0.20 m$

Therefore, the wave speed is

$v=(15500)(0.20)=3100 m/s$

4 0

2 years ago

Mention three bodies/organizations that need electricity 24 hours

Minchanka [31]

There are three types of electricity – baseload, dispatchable, and variable

5 0

2 years ago

What is the mass of a large ship that has a momentum of 1.60×109kg·m/s, when the ship is moving at a speed of 48.0 km/h? (b) Com

erastova [34]

a) The mass of the ship is $1.2\cdot 10^8 kg$

b) The ship has a larger momentum than the shell

Explanation:

a)

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is its velocity

For the ship in this problem, we have

$p=1.60\cdot 10^9 kg m/s$ is the momentum

$v=48.0 km/h \cdot \frac{1000 m/km}{3600 s/h}=13.3 m/s$ is the velocity

Solving for m, we find the mass of the ship:

$m=\frac{p}{v}=\frac{1.60\cdot 10^9}{13.3}=1.2\cdot 10^8 kg$

b)

The momentum of the artillery shell is given by

$p=mv$

where

m is its mass

v is its velocity

For the shell in this problem,

m = 1100 kg

v = 1200 m/s

Substituting,

$p=(1100)(1200)=1.32\cdot 10^6 kg m/s$

So, we see that the ship has a larger momentum.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

6 0

2 years ago

As a moon follows its orbit around a planet, the maximum grav- itational force exerted on the moon by the planet exceeds the min

Mars2501 [29]

The gravitational force exerted on the moon by the planet when the moon is at maximum distance $r_{max}$ is
$F_{min}=G \frac{Mm}{r_{max}^2}$
where G is the gravitational constant, M and m are the planet and moon masses, respectively. This is the minimum force, because the planet and the moon are at maximum distance.

Similary, the gravitational force at minimum distance is
$F_{max}=G \frac{Mm}{r_{min}^2}$
And this is the maximum force, since the distance between planet and moon is minimum.

The problem says that $F_{max}$ exceeds $F_{min}$ by 11%. We can rewrite this as
$F_{max}=(1+0.11)F_{min}=1.11 F_{min}$

Substituing the formulas of Fmin and Fmax, this equation translates into
$\frac{1}{r_{min}^2}=1.11 \frac{1}{r_{max}^2}$
and so, the ratio between the maximum and the minimum distance is
$\frac{r_{max}}{r_{min}}= \sqrt{ 1.11 }=1.05$

8 0

2 years ago