Answer:
This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:
Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.
Answer:
In the case of a solution transition metal complex that has an absorption peak at 450 nm in the blue region of the visible spectrum, the (complementary) color of this solution is orange (option B).
Explanation:
The portion of UV-visible radiation that is absorbed implies that a portion of electromagnetic radiation is not absorbed by the sample and is therefore transmitted through it and can be captured by the human eye. That is, in the visible region of a complex, the visible color of a solution can be seen and that corresponds to the wavelengths of light it transmits, not absorbs. The absorbing color is complementary to the color it transmits.
So, in the attached image you can see the approximate wavelengths with the colors, where they locate the wavelength with the absorbed color, you will be able to observe the complementary color that is seen or reflected.
<u><em>
In the case of a solution transition metal complex that has an absorption peak at 450 nm in the blue region of the visible spectrum, the (complementary) color of this solution is orange (option B).</em></u>
Answer:
(C) 4 beats per second.
Explanation:
As we know that the no of beats can be calculated as.
No. of beats is equal to difference in the tuning forks frequencies.
So,
.
Substitute the values of frequencies of 2 tuning forks in the above equation.
Therefore the number of beats per second will be hear by the observer is 4 beats per second.
Answer:633 m
Explanation:
First we have moved 300 m in North
let say it as point a and its vector is 
after that we have moved 500 m northeast
let say it as point b
therefore position of b with respect to a is
r
Therefore position of b w.r.t to origin is
![r_b=500cos(45)\hat{i}+\left [ 250\sqrt{2}+300\right ]\hat{j}](https://tex.z-dn.net/?f=r_b%3D500cos%2845%29%5Chat%7Bi%7D%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300%5Cright%20%5D%5Chat%7Bj%7D)
after this we moved 400 m 
south of east i.e. below from positive x axis
let say it as c
![r_c=500cos(45)\hat{i}+\left [ 250\sqrt{2}+300\right ]\hat{j}+400cos(60)\hat{i}-400sin(60)\hat{j}](https://tex.z-dn.net/?f=r_c%3D500cos%2845%29%5Chat%7Bi%7D%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300%5Cright%20%5D%5Chat%7Bj%7D%2B400cos%2860%29%5Chat%7Bi%7D-400sin%2860%29%5Chat%7Bj%7D)
![r_c=\left [ 250\sqrt{2}+200\right ]\hat{i}+\left [ 250\sqrt{2}+300-200\sqrt{3}\right ]\hat{j}](https://tex.z-dn.net/?f=r_c%3D%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B200%5Cright%20%5D%5Chat%7Bi%7D%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300-200%5Csqrt%7B3%7D%5Cright%20%5D%5Chat%7Bj%7D)
magnitude is ![\sqrt{\left [ 250\sqrt{2}+200\right ]^2+\left [ 250\sqrt{2}+300-200\sqrt{3}\right ]^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B200%5Cright%20%5D%5E2%2B%5Cleft%20%5B%20250%5Csqrt%7B2%7D%2B300-200%5Csqrt%7B3%7D%5Cright%20%5D%5E2%7D)
=633.052
for direction
with x -axis
