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igor_vitrenko [27]
1 year ago
8

Suppose you have a pendulum clock which keeps correct time on Earth(acceleration due to gravity = 1.6 m/s2). For ever hour inter

val (on Earth) the Moon clock:
A) (9.8/1.6)h
B) 1 h
C) the square root of 9.8/1.6 h
D) (1.6/9.8)h
E) the square root of 1.6/9.8 h
Physics
1 answer:
satela [25.4K]1 year ago
7 0

The time-period of a simple pendulum is

<em>Time =  2 π √(length/grav-accel)</em>

After unraveling the question, then completing it, and working out what I <em>believe</em> it's trying to ask, the choice that correctly answers the question that I have invented is <em>choice-E</em> .

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