Answer:
The speed of ejection is
Solution:
As per the question:
Magnetic field density, B = 0.4 T
Density of the material in the sunspot,
Now,
To calculate the speed of ejection of the material, v:
The magnetic field energy density is given by:
This energy density equals the kinetic energy supplied by the field.
Thus
where
m = mass of the sunspot in =
Answer:
E. downward and constant
Explanation:
Freefall is a special case of motion with constant acceleration because the acceleration due to gravity is always constant and downward. This is true even when an object is thrown upward or has zero velocity.
For example, when a ball is thrown up in the air, the ball's velocity is initially upward. Since gravity pulls the object toward the earth with a constant acceleration ggg, the magnitude of velocity decreases as the ball approaches maximum height. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth.
Answer:
mass of the person walking to west is 65 kg.
Given:
Momentum = 52
Speed = 0.8
To find:
Mass of the person = ?
Formula used:
Momentum is given by,
P = m × v
Where, P = momentum
m = mass
v = speed
Solution:
Momentum is given by,
P = m × v
Where, P = momentum
m = mass
v = speed
Mass =
m =
m = 65 kg
Thus, mass of the person walking to west is 65 kg.