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kirza4 [7]
2 years ago
5

An engineer is designing a process for a new transistor. She uses a vacuum chamber to bombard a thin layer of silicon with ions

of phosphorus, each of mass mP = 5.18 × 10-26 kg. The phosphorus ions are doubly ionized, with each phosphorus ion lacking two electrons. The ions start at rest at one end of the vacuum chamber and are accelerated by an electric field over a distance of re = 46 cm before they strike the silicon layer with velocity vP = 180 m/s. Calcultae the average electric field strength, E, across the vacum chamber.
Physics
1 answer:
adelina 88 [10]2 years ago
6 0

Answer:

E=5.7\times 10^{-3}\ V/m

Explanation:

Given that

m_p=5.18\times 10^{-26}\ kg

re= 46 cm

Vp= 180 m/s

We know that

E=\dfrac{\Delta V}{r}

\Delta V=\dfrac{1}{4}\dfrac{m_pv_p^2}{e}

So

E=\dfrac{1}{4}\dfrac{m_pv_p^2}{e.r_e}

Now by putting the all given values in the questions

E=\dfrac{1}{4}\times \dfrac{5.18\times 10^{-26}\times 180^2}{1.6\times 10^{-19}\times 0.46}

E=5.7\times 10^{-3}\ V/m

So the average electric field is E=5.7\times 10^{-3}\ V/m.

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A uniform sphere with mass M and radius R is rotating with angular speed ω1 about a frictionless axle along a diameter of the sp
liq [111]

Answer:

W_2=\sqrt{\frac{3}{5} }W_1

Explanation:

For the first ball, the moment of inertia and the kinetic energy is:

I_1 =\frac{2}{5}MR^2

K_1 = \frac{1}{2}IW_1^2

So, replacing, we get that:

K_1 = \frac{1}{2}(\frac{2}{5}MR^2)W_1^2

At the same way, the moment of inertia and kinetic energy for second ball is:

I_2 =\frac{2}{3}MR^2

K_2 = \frac{1}{2}IW_2^2

So:

K_2 = \frac{1}{2}(\frac{2}{3}MR^2)W_2^2

Then, K_2 is equal to K_1, so:

K_2 = K_1

\frac{1}{2}(\frac{2}{3}MR^2)W_2^2 = \frac{1}{2}(\frac{2}{5}MR^2)W_1^2

\frac{1}{3}MR^2W_2^2 = \frac{1}{5}MR^2W_1^2

\frac{1}{3}W_2^2 = \frac{1}{5}W_1^2

Finally, solving for W_2, we get:

W_2=\sqrt{\frac{3}{5} }W_1

5 0
2 years ago
Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the crit
Dennis_Churaev [7]

Complete Question:

A beam of white light is incident on the surface of a diamond at an angle \theta_{a},  since the index of refraction depends on the light's wavelength, the different colors that comprise white light will spread out as they pass through the diamond. For example, the indices of refraction in diamond are n_{red} = 2.410 for red light and n_{blue} = 2.450 for blue light. Thus, blue light and red light are refracted at different angles inside the diamond. The surrounding air has n_{air} = 1.000.

Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the critical angle θcrit, the light will not be refracted out into the air, but instead it will be totally internally reflected back into the diamond. Find θcrit. Express your answer in degrees to four significant figures.

Answer:

\theta_{crit} = 24.09^{0}

Explanation:

Only the blue refracted ray is related to the critical angle in this question

n_{air} = 1.000

n_{blue} = 2.450

The relationship between the critical angle(\theta_{crit}), n_{air} and n_{blue} can be given as sin \theta_{crit} = \frac{n_{air} }{n_{blue} }

sin \theta_{crit} = \frac{1 }{2.450 }\\\theta_{crit} = sin^{-1} \frac{1 }{2.450 }\\\theta_{crit} = sin^{-1} 0.4082^{0}\\  \theta_{crit} = 24.09^{0}

6 0
2 years ago
If the newton is the product of kilograms and meters/second2 what units comprise the pound?
Kobotan [32]

Answer:

Pound is the product of slug and foot/square second.

Explanation:

We are given that

Force=1 N

1N=1kg\times ms^{-2}

We have to find the units comprise the pound.

Force=1 Pound

Mass=Slug

Acceleration=ft/s^2

Therefore,

1 pound=1 slug\times fts^{-2}

Therefore, we can write as 1 pound is equal to the product of slug and ft/square second.

Hence, pound is the product of slug and foot/square second.

6 0
2 years ago
At 213.1 K a substance has a vapor pressure of 45.77 mmHg. At 243.7 K it has a vapor pressure of 193.1 mm Hg. Calculate its heat
vlabodo [156]

Answer:

20.3125 kJ/mol

Explanation:

P_{i} = initial vapor pressure = 45.77 mm Hg

P_{f} = final vapor pressure = 193.1 mm Hg

T_{i} = initial temperature = 213.1 K

T_{f} = final temperature = 243.7 K

H = Heat of vaporization

Using the equation

ln\left ( \frac{P_{f}}{P_{i}} \right ) = \left ( \frac{-H}{R} \right )\left ( \frac{1}{T_{f}} - \frac{1}{T_{i}}\right)

ln\left ( \frac{193.1}{45.77} \right ) = \left ( \frac{-H}{8.314} \right )\left ( \frac{1}{243.7} - \frac{1}{213.1}\right)

H = 20312.5 J/mol

H = 20.3125 kJ/mol

8 0
2 years ago
Tom and his little sister are enjoying an afternoon at the ice rink. they playfully place their hands together and push against
Westkost [7]
Newton's third law says:
"<span>For every action, there is an equal and opposite reaction. ".

So, the force that Tom does on the sister is equal to force the sister applies on Tom:
</span>F_t = F_s
<span>where the label "t" means "on Tom", while the label "s" means "on the sister".

From Newton's second law, we also know
</span>F=ma
where m is the mass and a the acceleration. <span>so we can rewrite the first equation as
</span>m_t a_t = m_s a_s
<span>And find Tom's acceleration:
</span>a_t =  \frac{m_s}{m_t} a_s =  \frac{15 kg}{61 kg} (2.1 m/s^2)  =0.52 m/s^2<span>
</span>
5 0
2 years ago
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