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Liono4ka [1.6K]
2 years ago
11

If the temperature is lowered from 60 °c to 30 °c, the volume of a fixed amount of gas will be one half the original volume. if

the temperature is lowered from 60 °c to 30 °c, the volume of a fixed amount of gas will be one half the original volume.
a. True
b. False
Physics
1 answer:
bazaltina [42]2 years ago
8 0
I believe it should be FALSE 

reply if i´m wrong.
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A woman makes 50% more than her husband. Together they make $2500 each month? How much does the woman earn each month?a) $950b)
Sergeeva-Olga [200]

Answer:b

Explanation:

Given

Woman earn 50% more than her husband

Total sum of their money is =\$ 2500

Suppose man earns \$ P

so women earns P+0.5 P=P(1+0.5)=1.5 P

Sum of their money is

P+1.5 P=2500

P=\$ 1000

Women earns =1.5\times 1000=\$ 1500          

6 0
1 year ago
A child of mass m is at the edge of a merry-go-round of diameter d. When the merry-go-round is rotating with angular acceleratio
dem82 [27]

Answer:

The torque on the child is now the same, τ.

Explanation:

  • It can be showed that the external torque applied by a net force on a rigid body, is equal to the product of the moment of inertia of the body with respect to the axis of rotation, times the angular acceleration.
  • In this case, as the movement of the child doesn't create an external torque, the torque must remain the same.
  • The moment of inertia is the sum of the moment of inertia of the merry-go-round (the same that for a solid disk) plus the product of  the mass of the child times the square of the distance to the center.
  • When the child is standing at the edge of the merry-go-round, the moment of inertia is as follows:

       I_{to} = I_{d} + m*r^{2}  = m*\frac{r^{2}}{2} +  m*r^{2} = \frac{3}{2}*  m*r^{2} (1)

  • So, τ = 3/2*m*r²*α (2)
  • When the child moves to a position half way between the center and the edge of the merry-go-round, the moment of inertia of the child decreases, as the distance to the center is less than before, as follows:

       I_{t} = I_{d} + m*\frac{r^{2}}{4}   = m*\frac{r^{2}}{2} + m*\frac{r^{2}}{4}  = \frac{3}{4}*  m*r^{2} (3)

  • Since the angular acceleration increases from α to 2*α, we can write the torque expression as follows:

       τ = 3/4*m*r² * (2α) = 3/2*m*r²

        same result than in (2), so the torque remains the same.

7 0
2 years ago
In an experiment, students release a block from rest at the top of an inclined plane. The block slides down the plane through a
mote1985 [20]

Answer:

B) Friction

Explanation:

The main source of error is the omission of the effect from friction between block and incline, which is directly proportional to the mass of the block. The force of gravity is constant. The friction force dissipates part of the gravitational potential energy, generating a final speed less than calculated under the consideration of a conservative system. Air resistance is neglected at low speeds like this case.

8 0
2 years ago
A 0.50 kilogram ball is held at a height of 20 meters. What is the kinetic energy of the ball when it reaches halfway after bein
Margarita [4]
Potential energy at any point is (M G H). On the way down, only H changes. So halfway down, half of the potential energy remains, and the other half has turned to kinetic energy. Half of the (M G H) it had at the tpp is (0.5 x 9.8 x 10) = 49 joules.
6 0
1 year ago
Read 2 more answers
A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled
sesenic [268]
Velocity =

(distance between start point and end point, regardless of the route traveled) / (time spent traveling).

That distance (called the "displacement"), is 10 meters, and almost exactly 1 hour is almost exactly 3,600 seconds. So the numerical value of the velocity during that time is

(10) / (3,600) = almost exactly 0.00278 m/s

= 2.78 x 10^-3 m/s.
3 0
2 years ago
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