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1 year ago

What type of weather modification involves the use of large fans to mix surface air with air aloft?

1 answer:

6 0

The type of weather modification is intentional weather modification. Intentional in such a way that there are practical methods applied in order to force/alter the weather condition. For example, frost prevention on crops. Farmers normally utilize large fans to get the warmer air from above to mix with the cold air near the ground surface. By doing so, crops are kept from being ruined by frost.

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An object’s velocity is measured to be vx(t) = α - βt2, where α = 4.00 m/s and β = 2.00 m/s3. At t = 0 the object is at x = 0. (

Leona [35]

Answer:

Explanation:

Given

$v_x(t)=\alpha -\beta t^2$

$\alpha =4\ m/s$

$\beta =2\ m/s^3$

$v_x(t)=4-2t^2$

$v=\frac{\mathrm{d} x}{\mathrm{d} t}$

$\int dx=\int \left ( 4-2t^2\right )dt$

$x=4t-\frac{2}{3}t^3$

acceleration of object

$a=\frac{\mathrm{d} v}{\mathrm{d} t}$

$a=-4t$

(b)For maximum positive displacement velocity must be zero at that instant

i.e. $v=0$

$4-2t^2=0$

$t=\pm \sqrt{2}$

substitute the value of t

$x=4\times \sqrt{2}-\frac{2}{3}\times 2\sqrt{2}$

$x=3.77\ m$

7 0

1 year ago

Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a

horsena [70]

Answer:

a)106.48 x 10⁵ kg.m²

b)144.97 x 10⁵ kgm² s⁻¹

Explanation:

a)Given

m = 5500 kg

l = 44 m

Moment of inertia of one blade

$I$ = 1/3 x m l²

where m is mass of the blade

l is length of each blade.

Putting all the required values, moment of inertia of one blade will be

$I$ = 1/3 x 5500 x 44²

$I$ = 35.49 x 10⁵ kg.m²

Moment of inertia of 3 blades

$I$ = 3 x 35.49 x 10⁵ kg.m²

$I$ = 106.48 x 10⁵ kg.m²

b) Angular momentum 'L' is given by

L = $I$ x ω

where,

$I$ = moment of inertia of turbine i.e 106.48 x 10⁵ kg.m²

ω=angular velocity =2π f

f is frequency of rotation of blade i.e 13 rpm

f = 13 rpm=>= 13 / 60 revolution per second

ω = 2π f => 2π x 13 / 60 rad / s

L= $I$ x ω =>106.48 x 10⁵ x 2π x 13 / 60

= 144.97 x 10⁵ kgm² s⁻¹

7 0

1 year ago

A submarine completed a 450 km training with an average speed of 50 km/h. For the first 180 km, it travelled at an average speed

Kryger [21]

Answer:

45km/hr

Explanation:

Total distance=450km

Total speed=50km/hr

Total time= distance/speed

=450/50

=9hrs

distance a=180km

speed a=60km/hr

Time a=180/60

=3hrs

Distance b=450-180=270km

Speed b=?

Time b=270/speed b

Total time=time a + time b

9=3+(270/speed b)

270/speed b =9-3

270/speed b =6

6*speed b =270

Speed b=270/6

Speed b=45km/hr

4 0

1 year ago

Calculate the acceleration of the body of mass 3kg on which a force of 42N has been applied for 5s

____ [38]

F=ma

42/3 = a
a = 14m/s^2

5 0

2 years ago

Julius competes in the hammer throw event. the hammer has a mass of 7.26 kg and is 1.215 m long. what is the centripetal force o

TEA [102]

Centripetal force <span>a force that acts on a body moving in a circular path and is directed toward the center around which the body is moving. It is calculated by the expression:

F = mv^2/r

where m is the mass, v is the velocity and r is the radius.

F = 7.26(31.95)^2 / (1.215) = 6100 N</span>

8 0

1 year ago

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