What type of weather modification involves the use of large fans to mix surface air with air aloft?
1 answer:
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Answer:
σ₁ = C/m²
σ₂ = C/m²
Explanation:
The given data :-
i) The radius of smaller sphere ( r ) = 5 cm.
ii) The radius of larger sphere ( R ) = 12 cm.
iii) The electric field at of larger sphere ( E₁ ) = 358 kV/m. = 358 * 1000 v/m
Q₁ = 572.8 C
Since the field inside a conductor is zero, therefore electric potential ( V ) is constant.
V = constant
∴
=
C
Surface charge density ( σ₁ ) for large sphere.
Area ( A₁ ) = 4 * π * R² = 4 * 3.14 * 0.12 = 0.180864 m².
σ₁ = =
=
C/m².
Surface charge density ( σ₂ ) for smaller sphere.
Area ( A₂ ) = 4 * π * r² = 4 * 3.14 * 0.05² =0.0314 m².
σ₂ = =
=
C/m²
Answer:
<h3>The answer is 4.29 m/s²</h3>Explanation:
The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula
From the question
velocity = 30 m/s
time = 7 s
We have
We have the final answer as
<h3>4.29 m/s²</h3>Hope this helps you