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In-s [12.5K]
2 years ago
6

A cart moves along a track at a velocity of 3.5 cm/s. When a force is applied to the cart, its velocity increases to 8.2 cm/s. I

f it takes the cart 1.5 seconds to reach 8.2 cm/s, what is the acceleration of the cart? Round your answer to the nearest tenth. cm/s2
Physics
2 answers:
zheka24 [161]2 years ago
5 0
The first thing we are going to do for this case is write the equations of movement of the car.
 We have then:
 vf = a * t + vo
 Substituting values:
 8.2 = a * (1.5) + (3.5)
 Clearing the acceleration we have:
 a = (8.2-3.5) / (1.5)
 a = 3.1 m / s ^ 2
 Answer: 
 the acceleration of the cart is: 
 a = 3.1 m / s ^ 2
9966 [12]2 years ago
5 0

Answer:

3.1cm/s^2

Explanation:

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Explanation:

Given that,

Displacement in ice block, d=14i-11j

Force exerted by water, F=158i-179j

To find,

Work done by the force during the displacement.

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W=(158i-179j).(14i-11j)

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W=2212+1969=4181\ J

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A 4.0 Ω resistor, an 8.0 Ω resistor, and a 12.0 Ω resistor are connected in parallel across a 24.0 V battery. What is the equiva
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PART A)

Equivalent resistance in parallel is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

now we have

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PART B)

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PART C)

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for 8 ohm resistance we have

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10,000 units of momentum.
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Utility poles are to be set every 30 meters. How many poles will be set in one mile if one was set at the beginning of the mile)
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Answer:

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