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Inessa [10]
1 year ago
9

If two waves with identical crests and troughs meet, what is happening? The wave is reflecting. Constructive interference is occ

urring. The wave is breaking. Destructive interference is occurring. Save
Physics
2 answers:
Kazeer [188]1 year ago
7 0
The correct answer would be that destructive interference is happening. In this interference, the crest of a wave meets a trough of another wave resulting to an amplitude that is lower. The opposite is called the constructive interference. Hope this answers the question.
soldi70 [24.7K]1 year ago
7 0

The answer is: A. Constructive interference is occurring.

Hope this helped! :)

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A lump of steel of mass 10kg at 627 degree Celsius is dropped in 100kg oil at 30 degree Celsius . the specific heat of steel And
Naily [24]

Answer:

700J

Explanation:

8 0
1 year ago
Consider an optical cavity of length 40 cm. Assume the refractive index is 1, and use the formula for Icavity vs wavelength to p
Bad White [126]

Answer:

Diode Lasers  

Consider a InGaAsP-InP laser diode which has an optical cavity of length 250  

microns. The peak radiation is at 1550 nm and the refractive index of InGaAsP is  

4. The optical gain bandwidth (as measured between half intensity points) will  

normally depend on the pumping current (diode current) but for this problem  

assume that it is 2 nm.  

(a) What is the mode integer m of the peak radiation?  

(b) What is the separation between the modes of the cavity? Please express your  

answer as Δλ.  

(c) How many modes are within the gain band of the laser?  

(d) What is the reflection coefficient and reflectance at the ends of the optical  

cavity (faces of the InGaAsP crystal)?  

(e) The beam divergence full angles are 20° in y-direction and 5° in x-direction  

respectively. Estimate the x and y dimensions of the laser cavity. (Assume the  

beam is a Gaussian beam with the waist located at the output. And the beam  

waist size is approximately the x-y dimensions of the cavity.)  

Solution:  

(a) The wavelength λ of a cavity mode and length L are related by  

n

mL

2

λ = , where m is the mode number, and n is the refractive index.  

So the mode integer of the peak radiation is  

1290

1055.1

10250422

6

6

= ×

××× == −

−

λ

nL

m .  

(b) The mode spacing is given by nL

c f 2

=Δ . As

λ

c f = , λ

λ

Δ−=Δ 2

c f .  

Therefore, we have nm

nL f

c

20.1

)10250(42

)1055.1(

2 || 6

2 2 26

= ×××

× ==Δ=Δ −

− λλ λ .  

(c) Since the optical gain bandwidth is 2nm and the mode spacing is 1.2nm, the  

bandwidth could fit in two possible modes.  

For mode integer of 1290, nm

m

nL 39.1550

1290

10250422 6

= ××× ==

−

λ

Take m = 1291, nm

m

nL 18.1549

1291

10250422 6

= ××× ==

−

λ

Or take m = 1289, nm

m

nL 59.1551

1289

10250422 6

= ××× ==

−

λ .

Explanation:

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2 years ago
Tom’s company has been contracted to excavate uranium ore with minimal ground disruption. What process should his company use?
ziro4ka [17]
In-situ leaching or solution mining offers the least ground disruptive type of mining and waste.  This type of mining only dissolves the uranium where it is under the ground then pump up to the ground and further processed through milling. 
7 0
1 year ago
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A 1 kg coconut falls vertically from a height of 10 meters. Use the principle of conservation of mechanical
Kay [80]

Answer:

Explanation:

Question 1:

Mass=1kg

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Question 2:

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98=(1 x(velocity))^2 ➗ 2

Cross multiplying

98 x 2=(velocity)^2

196=(velocity)^2

Velocity=√(196)

Velocity=14

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5 0
2 years ago
A 2600-m-high mountain is located on the equator. how much faster does a climber on top of the mountain move than a surfer at a
puteri [66]

The climber move 0.19 m/s  faster than surfer on the nearby beach.

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The linear speed on the beach is calculated as

V1=\frac{2πr}{t}

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Therefore person on the mountain moves faster than the person on the beach by 465.61-465.421=0.19 m/s

5 0
1 year ago
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