Answer:
T = 570 N
Explanation:
Given that,
The gravitational force acting on a bucket of water = 525 N
Net force in the Y direction is 45 N
We need to find the magnitude of the force of tension. It can be calculated as :
45 = T - 525
T = 525 + 45
T = 570 N
Hence, the force of tension is 570 N.
Answer:
vB' = 0.075[m/s]
Explanation:
We can solve this problem using the principle of linear momentum conservation, which tells us that momentum is preserved before and after the collision.
Now we have to come up with an equation that involves both bodies, before and after the collision. To the left of the equal sign are taken the bodies before the collision and to the right after the collision.
where:
mA = 0.355 [kg]
vA = 0.095 [m/s] before the collision
mB = 0.710 [kg]
vB = 0.045 [m/s] before the collision
vA' = 0.035 [m/s] after the collision
vB' [m/s] after the collison.
The signs in the equation remain positive since before and after the collision, both bodies continue to move in the same direction.
![(0.355*0.095)+(0.710*0.045)=(0.355*0.035)+(0.710*v_{B'})\\v_{B'}=0.075[m/s]](https://tex.z-dn.net/?f=%280.355%2A0.095%29%2B%280.710%2A0.045%29%3D%280.355%2A0.035%29%2B%280.710%2Av_%7BB%27%7D%29%5C%5Cv_%7BB%27%7D%3D0.075%5Bm%2Fs%5D)
The two forces should be equal therefore:
2.10 * Fa = Fa + 2 * F * cos 18
simplifying the right side:
2.10 * Fa = Fa + 1.902 * F
1.10 Fa = 1.902 F
<span>F / Fa = 0.578</span>
To solve this question, we need to use the component method and split our displacements into their x and y vectors. We will assign north and east as the positive directions.
The first movement of 25m west is already split. x = -25m, y = 0m.
The second movement of 45m [E60N] needs to be split using trig.
x = 45cos60 = 22.5m
y = 45sin60 = 39.0m
Then, we add the two x and two y displacements to get the total displacement in each direction.
x = -25m + 22.5m = -2.5m
y = 0m + 39.0m
We can use Pythagorean theorem to find the total displacement.
d² = x² + y²
d = √(-2.5² + 39²)
d = 39.08m
And then we can use tan to find the angle.
inversetan(y/x) = angle
inversetan(39/2.5) = 86.3
Therefore, the total displacement is 39.08m [W86.3N]
