Below are the choices that can be found in the other sources:
A. diffraction
<span>B. refraction </span>
<span>C. reflection </span>
<span>D. transmission
</span>
The answer is diffraction. It means that <span>the process by which a beam of light or other system of waves is spread out as a result of passing through a narrow aperture or across an edge, typically accompanied by interference between the wave forms produced.</span>
Answer:

Explanation:
Let m be the mass of a little car and m' be the mass of another car.
We know that,
Force = mass × acceleration
ATQ,
m × a = 2m × a'
a = 2 × a'

So, the acceleration of another little car is equal to
.
Answer:

Explanation:
<u>Free Fall Motion</u>
A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.
The speed vf of the object when a time t has passed is given by:

Where 
Similarly, the distance y the object has traveled is calculated as follows:

If we know the height h from which the object was dropped, we can solve the above equation for t:

The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:

The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:

Therefore, it has traveled down a distance:

Thus, the height of the pen is:

Answer:
a = 18.28 ft/s²
Explanation:
given,
time of force application, t= 10 s
Work = 10 Btu
mass of the object = 15 lb
acceleration, a = ? ft/s²
1 btu = 778.15 ft.lbf
10 btu = 7781.5 ft.lbf

m = 0.466 slug
now,
work done is equal to change in kinetic energy

now, acceleration of object


a = 18.28 ft/s²
constant acceleration of the object is equal to 18.28 ft/s²
W=ΔKE , W=-5000j
KEinitial=(1/2)mv² , KEfinal=0j
ΔKE=-(1/2)mv²
-5000=-(1/2)(100kg)v²
v=10 m/s