Answer:
I. The horizontal distance traveled by the bullet is greater for the Moon.
II. The flight time is less for the bullet on the Earth.
Explanation:
Horizontal distance depends on the initial speed, height and gravity. Bullets have the same initial speed and are shot from the same height. In these conditions horizontal distance only depends on gravity, which is inversely proportional. Therefore, the less gravity the greater the horizontal distance. Gravity slows bullet and causes its impact on the ground. Since gravity is greater in Earth, the bullet hits faster on the earth.
Which amplitude of the following longitudinal waves has the greatest energy?
amplitude = 10 cm; wavelength = 6 cm; period = 4 seconds
Answer:
Second pit is 375 m deeper compared to first pit.
Explanation:
We have equation of motion s = ut + 0.5at²
First object hits the ground after 5 seconds,
Initial velocity, u = 0 m/s
Acceleration, a = 10 m/s²
Time, t = 5 s
Substituting,
s = ut + 0.5 at²
s = 0 x 5 + 0.5 x 10 x 5²
s = 125 m
Depth of pit 1 = 125 m
Second object hits the ground after 10 seconds,
Initial velocity, u = 0 m/s
Acceleration, a = 10 m/s²
Time, t = 10 s
Substituting,
s = ut + 0.5 at²
s = 0 x 10 + 0.5 x 10 x 10²
s = 500 m
Depth of pit 2 = 500 m
Difference in depths = 500 - 125 = 375 m
Second pit is 375 m deeper compared to first pit.
Answer:
a. N = 2.49W b. 0.40
Explanation:
a. What is the magnitude of the normal force FNFN between a rider and the wall, expressed in terms of the rider's weight W?
Since the normal force equals the centripetal force on the rider, N = mrω² where r = radius of cylinder = 3.05 m and ω = angular speed of cylinder = 0.450 rotations/s = 0.450 × 2π rad/s = 2.83 rad/s
Now N = mrω² = m(3.05 m) × (2.83 rad/s)² = 24.43m
The rider's weight W = mg = 9.8m
The ratio of the normal force to the rider's weight is
N/W = 24.43m/9.8m = 2.49
So the normal force expressed in term's of the rider's weight is
N = 2.49W
b. What is the minimum coefficient of static friction µsμs required between the rider and the wall in order for the rider to be held in place without sliding down?
The frictional force, F on the rider by the wall of the cylinder equals the weight, W of the rider. F = W.
Since the frictional force F = μN, where μ = coefficient of static friction between rider and wall of cylinder and N = normal force between rider and wall of cylinder.
So, the normal force equals
N = F/μ = W/μ = mg/μ = mrω²
μ = mg/mrω²
= W/N
= 9.8m/24.43m
= 0.40
<span>When the particles of a medium move with simple harmonic motion, this means the wave is a sinusoidal wave.
Know that a sinusoidal curve can describe either sine or cosine functions (remember your cofunction identities for sine and cosine).</span>
