A rope exerts a force F on a 20.0-kg crate. The crate starts from rest and accelerates upward at 5.00 m/s2 near the surface of t
1 answer:
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Answer:
ω2 = 216.47 rad/s
Explanation:
given data
radius r1 = 460 mm
radius r2 = 46 mm
ω = 32k rad/s
solution
we know here that power generated by roller that is
power = T. ω ..............1
power = F × r × ω
and this force of roller on cylinder is equal and opposite force apply by roller
so power transfer equal in every cylinder so
( F × r1 × ω1) ÷ 2 = ( F × r2 × ω2 ) ÷ 2 ................2
so
ω2 =
ω2 = 216.47
Answer: m= 35.6 kg
Explanation:
For finding the mass of the stone we have the formula
v=
Here, Tension= m*g = m*9.81
and linear mass density=
Linear mass density=
Linear mass density= 0.0127 kg/m
Velocity=
Velocity= 2 *
Velocity= 165.8 m/s
So putting all these values in equation we get
v=
165.8=
Solving we get
m= 35.58 kg
or m= 35.6 kg
Answer:
Explanation:
Given:
- width of door,
- height of the door,
- thickness of the door,
- mass of the door,
- torque on the door,
<em>∵Since the thickness of the door is very less as compared to its other dimensions, therefore we treat it as a rectangular sheet.</em>
- For a rectangular sheet we have the mass moment of inertia inertia as:
We have a relation between mass moment of inertia, torque and angular acceleration as: