Answer:
a)693.821N/m
b)17.5g
Explanation:
We the Period T we can find the constant k,
That is

squaring on both sides,

where,
M=hanging mass, m = spring mass,
k =spring constant
T =time period
a) So for the equation we can compare, that is,

the hanging mass M is x here, so comparing the equation we know that

b) In order to find the mass of the spring we make similar process, so comparing,

Answer:
a) V = 1.866 10² V
, b) V = 3.424 10⁵ V
, c) v = 8.1 10⁶ m / s
Explanation:
a) the potential difference is requested to accelerate the electrons up to 2.7% of the speed of light
v = 0.027 c
v = 0.027 3 10⁸
v = 8.1 10⁶ m / s
for this part we can use the conservation of mechanical energy
starting point. When electrons are at rest
Em₀ = U = q V
final point. Electrons with maximum speed
Em_f = K = ½ m v2
Em₀ = Em_{f}
e V = ½ m v²
V = ½ m v² / e
let's calculate
V = ½ 9.1 10⁻³¹ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 1.866 10² V
V = 1866 V
b) if this acceleration protons is the mass of the proton is m_{p} = 1.67 10-27
V = ½ 1.67 10⁻²⁷ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 3.424 10⁵ V
V = 342402 V
c)
this potential difference should give the protons the same speed as the electrons
v = 8.1 10⁶ m / s
Answer:
a) 
b) 
c) 
Explanation:
From the exercise we know that the ball strikes the building 16m away and its final height is 8m more than the initial
Being said that, we can calculate the initial velocity of the ball
a) First we analyze its horizontal motion


(1)
That would be our first equation
Now, we need to analyze its vertical motion


Knowing
in our first equation (1)


Solving for t

So, the ball takes to seconds to get to the other building. Now we can calculate its <u>initial velocity</u>

b) To find the <u>magnitude of the ball just before it strikes the building</u> we need to calculate its x and y components


So, the magnitude of the velocity is:

c) The <u><em>direction of the ball</em></u> is:

okay this is kinda easy
<u>What is the gravitational field strength on the moon?</u>
The Moon has a gravitational field strength of 1.6 N/kg.
Answer:
Spring constant, k = 0.3 N/m
Explanation:
It is given that,
Force acting on DNA molecule, 
The molecule got stretched by 5 nm, 
Let k is the spring constant of that DNA molecule. It can be calculated using the Hooke's law. It says that the force acting on the spring is directly proportional to the distance as :



k = 0.3 N/m
So, the spring constant of the DNA molecule is 0.3 N/m. Hence, this is the required solution.