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Salsk061 [2.6K]
2 years ago
7

When a resistor with resistance R is connected to a 1.50-V flashlight battery, the resistor consumes 0.0625 W of electrical powe

r. (Throughout, assume that each battery has negligible internal resistance.) What power does the resistor consume if it is connected to a 12.6-V car battery? Assume that R remains constant when the power consumption changes.
Physics
1 answer:
ch4aika [34]2 years ago
5 0

Answer:

4.41 W

Explanation:

P = IV, V = IR

P = V² / R

Given that P = 0.0625 when V = 1.50:

0.0625 = (1.50)² / R

R = 36

So the resistor is 36Ω.

When the voltage is 12.6, the power consumption is:

P = (12.6)² / 36

P = 4.41

So the power consumption is 4.41 W.

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A ray of light passes from air into carbon disulfide (n = 1.63) at an angle of 28.0 degrees to the normal. what is the refracted
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We can solve the problem by using Snell's law, which states 
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In our problem, n_i=1.00 (refractive index of air), \theta_i = 28.0^{\circ} and n_r=1.63 (refractive index of carbon disulfide), therefore we can re-arrange the previous equation to calculate the angle of refraction:
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Answer:

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Explanation:

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