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2 years ago

5

A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through th

e wire, it heats up and melts ice and snow on the window. For one window the wire has a total length of 12.2 m, a width of 1.8 mm, and a thickness of 0.11 mm. The wire is connected to the car's 12.0 V battery and draws 7.5 A. What is the resistivity of the wire material?

2 answers:

babunello [35]2 years ago

7 0

Answer: 2.6*10^-8 Ωm

Explanation:

given

Length of the wire, l = 12.2 m

width of the wire, w = 1.8 mm

thickness of the wire, T = 0.11 mm

Potential difference of the battery, v = 12 V

Current in the battery, I = 7.5 A

Remember, Ohms law says, V = IR.

So that, R = V/I

R = 12/7.5 = 1.6 Ω

Resistivity if a material is

ρ = RA/l

ρ = [1.6 * 1.8*10^-3 * 0.11*10^-3] / 12.2

ρ = (3.168*10^-7) / 12.2

ρ = 2.596*10^-8

Therefore, the resistivity of the wire is 2.60*10^-8 Ωm

Setler [38]2 years ago

7 0

Answer:

Answer is given below.

Explanation:

resistance = voltage / current

R = V/I

= 12 / 7.5 = 1.6 ohm

R = pL/A

where p = resistivity

L = length , A = cross sectional area

1.6 = p*12.2 / (1.6*10^-3*0.11*10^-3)

p = 2.3*10^-8 ohm - m

so the resistivity of the material is 2.3*10^-8 ohm - m

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