Answer:
33.725 rpm
Explanation:
The relationship between rotational speed in radians per second and acceleration is ...

We want the rotation rate in RPM, so we need the conversion ...

Then the required rotational speed in RPM is ...

The rotation rate needs to be about 33.7 rpm to give an acceleration of 1.4g at the astronaut's feet.
Okay, here is my stab at this, I hope it helps!
You know the bullet's initial velocity, V₀ = 450 m/s
You know the final velocity, V = 220 m/s
You also know how long the bullet accelerates (actually decelerates), 14cm, or .14 m
With this information, you learn that you need this equation.
V² = V₀² + 2a (x - x₀), because we have all the information except a, which is the acceleration. So putting it into the equation, it looks like this.
(220m/s)² = (450m/s)² +2a(.14m - 0m)
I'll let you solve the rest, but here are some hints. Your answer will be really big because the bullet slows down really quickly in a really small distance, and you answer will be negative, because this acceleration is causing the bullet to go slower, which is also called deceleration. Hope that helps!
Answer:
r= 2.17 m
Explanation:
Conceptual Analysis:
The electric field at a distance r from a charge line of infinite length and constant charge per unit length is calculated as follows:
E= 2k*(λ/r) Formula (1)
Where:
E: electric field .( N/C)
k: Coulomb electric constant. (N*m²/C²)
λ: linear charge density. (C/m)
r : distance from the charge line to the surface where E calculates (m)
Known data
E= 2.9 N/C
λ = 3.5*10⁻¹⁰ C/m
k= 8.99 *10⁹ N*m²/C²
Problem development
We replace data in the formula (1):
E= 2*k*(λ/r)
2.9= 2*8.99 *10⁹*(3.5*10⁻¹⁰/r)
r =( 2*8.99 *10⁹*3.5*10⁻¹⁰) / (2.9)
r= 2.17 m
km x h = km/h
First trial: 6 x 1 = 6km/h
Second trial: 9 x 2 = 18km/h
6 + 18 = <u>24km/h</u> (Total)
Or
6 + 9 = 15 km
2 + 1 = 3h
15 + 3 = 18
15 x 2 = 30
3 x 2 = 6
30 - 6 = <u>24km/h</u>