A worker pushes a 7 kg shipping box along a roller track. Assume friction is small enough to be ignored because of the rollers.
The worker's push is 25 N directed down and to the right at an angle of 20°.
(a) Determine the horizontal component of the worker's push.
(b) Write a net force equation for the horizontal forces on the box.
(a) Determine the horizontal component of the worker's push.
(b) Write a net force equation for the horizontal forces on the box.
1 answer:
Answer:
a) Fₓ = 23.5 N
b) Net force = Fₓ
Explanation:
An image of the question as described is attached to this solution.
From the image attached, the forces acting on the box include the weight of the box, the normal reaction of the surface on the box, the applied force on the box and the Frictional force opposing the motion of the box (which is negligible and equal to 0)
a) From the diagram, the horizontal component of the force is
Fₓ = 25 cos 20° = 23.49 N = 25 N
b) Again, from the diagram attached, doing a force balance on the box, in the horizontal direction, we obtain
Net force = Fₓ - Frictional force
But frictional force is 0 N
Net force = Fₓ
Hope this Helps!!!
You might be interested in
Answer:
The coin has a diameter of 2.67 cm
Explanation:
First, we need to find the volume of each coin by dividing the total volume of silver by the number of coins. We have also to do a conversion of units in terms of centimeters as follows:
Then, we define the coin as a tiny cilinder to determine its diameter. In that order we use the cilinder's volumen equation as follows:
Finally, we know that the diameter is twice the radius, therefore the diameter of each coin is 2.67 cm.
Answer:
towards left
Explanation:
As we know that there is no external force on the system of two cart so total momentum of the system is conserved
so we will say
now plug in all data into the above equation
here we assumed that left direction of motion is negative while right direction is positive
so we can solve it for speed v now