Question

Trained dolphins are capable of a vertical leap of 7.0m straight up from the surface of the water-an impressive feat.Suppose you could train a dolphin to launch itself out of the water at this same speed but at an angle.What maximum horizontal range could the dolphin achieve?

Answer 1

Answer:

   θ = 45º

Explanation:

To find the solution, let's use the projectile launch equation

    R = vo² sin 2θ / g

Where vo is the initial speed of the dolphin, T is the angle of the jump and g the gravity acceleration.

To obtain a maximum range, the sine T function must be 1,

     sin 2θ = 1

     2θ = sin⁻¹ 1

     2θ = 90

     θ = 45º

Therefore, the dolphin should jump at an angle of 45º from the horizontal