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fenix001 [56]
2 years ago
9

A block of mass 0.1 kg is attached to a spring of spring constant 22 N/m on a frictionless track. The block moves in simple harm

onic motion with amplitude 0.29 m. While passing through the equilibrium point from left to right, the block is struck by a bullet, which stops inside the block. The velocity of the bullet immediately before it strikes the block is 41 m/s and the mass of the bullet is 1.23 g.
A) Find the speed of the block immediately before the collision.Answer in units of m/sB) If the simple harmonic motion after the collision is described by x = B sin(? t + f), what is the new amplitude B?Answer in units of mC) The collision occurred at the equilibrium position.How long will it take for the block to reach maximum amplitude after the collision?Answer in units of s
Physics
1 answer:
Tasya [4]2 years ago
6 0

Answer:

(A) v = 14.8m/s

Explanation:

(A) V = sqrt(k/m) × A = sqrt(22/0.1) × 0.29 =14.8m/s.

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Answer:

2.39 revolutions

Explanation:

As she jumps off the platform horizontally at a speed of 10m/s, the gravity is the only thing that affects her motion vertically. Let g = 10m/s2, the time it takes for her to fall 10m to water is

h = gt^2/2

10 = 10t^2/2

t^2 = 2

t = \sqrt{2} = 1.414 s

Knowing the time it takes to fall to the pool, we calculate the angular distance that she would make at a constant acceleration of 15 rad/s2:

\theta = \alpha t^2/2

\theta = 15 * 2/2 = 15 rad

As each revolution is 2π, the total number of revolution that she could make is: 15 / 2π = 2.39 rev

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Which condition in a nebula would prevent nuclear fusion?
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The A-string (440 HzHz) on a piano is 38.9 cmcm long and is clamped tightly at both ends. If the string tension is 667N, what's
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Answer:

Mass, m = 2.2 kg                                

Explanation:

It is given that,

Frequency of the piano, f = 440 Hz

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The frequency in the spring is given by :

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\mu=\dfrac{m}{L} is the linear mass density

On rearranging, we get the value of m as follows :

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