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Mazyrski [523]
2 years ago
6

The value of gravitational acceleration of a body on Earth is 9.8 meters/second2. The gravitational potential energy for a 1.00

kilogram
object is found to be 12.5 joules. How high is this object above the ground level, where PE = 0?
O A. 1.3 meters
OB. 3.5 meters
OC. 2.0 meters
OD. 5.6 meters
O E. 7.9 meters
Physics
1 answer:
ANTONII [103]2 years ago
5 0

Answer:

A

Explanation:

i don't know but u think the answer is A

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Physics professor Antonia Moreno is pushed up a ramp inclined upward at an angle 31.0 ∘ above the horizontal as she sits in her
DerKrebs [107]

Answer:

The answer is below

Explanation:

Given that:

mass (m) = 86 kg, distance (L) = 2.75 m, θ = 31°, force (F) = 595 N, initial velocity (v_i) = 2.4 m/s, g = acceleration due to gravity = 9.8 m/s²

The net work can be gotten from the equation:

W_{net}=Fcos(\theta)L-mgsin(\theta)L\\\\W_{net}=595*cos(31)*2.75-[86*9.81*sin(31)*2.75)\\\\W_{net}=1402.54-1194.92\\\\W_{net}=207.62

From the work-energy theorem equation, we can get her speed at the top of the ramp (v_f)

Hence:

W_{net}=change\ in\ kinetic\ energy\\\\W_{net}=\frac{1}{2}m(v_f^2-v_i^2 )\\\\2W_{net}=m(v_f^2-v_i^2 )\\\\v_i=\sqrt{ v_i^2+\frac{2W_{net}}{m}} \\\\v_f=\sqrt{ 2.4^2+\frac{2*207.62}{86}}}\\\\v_f=3.25\ m/s

8 0
2 years ago
Q 32.35: The isotope 235U decays by alpha emission with a half-life of 7.0 x 108 y. It also decays (rarely) by spontaneous fissi
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Answer:

rate of fission =5.89*10^3 1\Year

Explanation:

we know that

rate of fission is given asrate of fission = \frac{0.69}{(T_{1/2})_{fission}} *\frac{ Mass* Avogardo\ number}{Molar\ mass}

(T_{1/2})_{fission} = 3*10^{17} y

mass = 1.0 g

avogardo number = 6.02*10^23

molar mass of isotopes 235U =235

Putting all value to get rate of emission

rate of fission = \frac{0.69}{3*10^{17}} *\frac{1.0*6.02*10^{23}}{235}

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A capacitor with plates separated by distance d is charged to a potential difference ΔVC. All wires and batteries are disconnect
fgiga [73]

Answer:

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