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Stella [2.4K]
2 years ago
13

Physics professor Antonia Moreno is pushed up a ramp inclined upward at an angle 31.0 ∘ above the horizontal as she sits in her

desk chair, which moves on frictionless rollers. The combined mass of the professor and chair is 86.0 kg . She is pushed a distance 2.75 m along the incline by a group of students who together exert a constant horizontal force (not parallel to the incline) of 595 N . Dr. Moreno's speed at the bottom of the ramp is 2.40 m/s
Physics
1 answer:
DerKrebs [107]2 years ago
8 0

Answer:

The answer is below

Explanation:

Given that:

mass (m) = 86 kg, distance (L) = 2.75 m, θ = 31°, force (F) = 595 N, initial velocity (v_i) = 2.4 m/s, g = acceleration due to gravity = 9.8 m/s²

The net work can be gotten from the equation:

W_{net}=Fcos(\theta)L-mgsin(\theta)L\\\\W_{net}=595*cos(31)*2.75-[86*9.81*sin(31)*2.75)\\\\W_{net}=1402.54-1194.92\\\\W_{net}=207.62

From the work-energy theorem equation, we can get her speed at the top of the ramp (v_f)

Hence:

W_{net}=change\ in\ kinetic\ energy\\\\W_{net}=\frac{1}{2}m(v_f^2-v_i^2 )\\\\2W_{net}=m(v_f^2-v_i^2 )\\\\v_i=\sqrt{ v_i^2+\frac{2W_{net}}{m}} \\\\v_f=\sqrt{ 2.4^2+\frac{2*207.62}{86}}}\\\\v_f=3.25\ m/s

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Answer:

Explanation:

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2 years ago
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3) A defense football player on one team tackles the other team’s quarterback, who is running down the field. The quarterback is
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Newton's first law says that an object at rest tends to stay at rest while an object in motion stays in motion at a constant velocity unless acted upon by an outside force so the amount of force behind the defensive football player (N) was greater than the quarterback's so he was able to over power him which is also called unbalanced forces
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A cart is pushed to the right with a force of 15 N while being pulled to the left with a force of 20 N. The net force on the car
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The net force of the cart when it is pushed to the right with a force of 15N.

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The Net Force here is given by

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The famous cliff divers of Acapulco leap from a perch 35 m above the ocean. How fast are they moving when they reach the surface
Rus_ich [418]

1) 26.2 m/s

The mechanical energy of the divers at any point of their vertical motion is sum of the kinetic energy and the gravitational potential energy:

E=K+U = \frac{1}{2}mv^2 + mgh

where

m is the mass of the diver

v is the speed

g = 9.8 m/s^2 is the acceleration due to gravity

h is the height above the water

When the diver is on the cliff, v = 0 (he is at rest), so K=0 and the initial mechanical energy is just potential energy:

E_i = mgh

where h=35 m is the height of the cliff.

When the diver hits the water above, h = 0, so U=0 and the final mechanical energy is just kinetic energy:

E_f = \frac{1}{2}mv^2

since the total mechanical energy is conserved, we have

E_i = E_f\\mgh = \frac{1}{2}mv^2

And solving the equation for v, we find the speed when they reach the surface of the water:

v=\sqrt{2gh}=\sqrt{2(9.8 m/s^2)(35 m)}=26.2 m/s

2) It is converted into thermal energy of the water

When the diver enters the water, he suddenly feels another force acting against the motion of the diver: the resistance of the water. The resistance of the water acts upward, slowing down the diver until he stops.

In this process, the speed of the diver (v) decreases, and therefore the kinetic energy of the diver decreases as well, until it becomes zero.

However, this does not mean that the conservation of energy has been violated. In fact, the kinetic energy of the diver has been converted into thermal energy of the molecules of water surrounding the diver.

8 0
2 years ago
A 0.200 kg plastic ball moves with a velocity of 0.30 m/s. It collides with a second plastic ball of mass 0.100 kg, which is mov
zzz [600]

Answer:

0.22m/s

Explanation:

The total momentum of the System is conserved. Total momentum of the system before the collision is equal to the total momentum of the system after collision. The total momentum is the sum of individual momentum of all the objects in that system.

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Total Momentum before collision = 0.2*0.3 + 0.1*0.1= 0.07 kg⋅m/s;

Total momentum after collision = 0.1*0.26 + 0.2*x = 0.07;

Solve for x.

4 0
2 years ago
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