Two speakers face each other, and they each emit a sound of wavelength λ. One speaker is 180∘ out of phase with respect to the o
ther. If we separate the speakers by a distance 1.5λ, how far from the left-most speaker should we place a microphone in order to pick up the loudest sound? Ignore reflections from nearby surfaces. Select all that apply.a. 3/4λb. 0 λc. 1/2λd. 1/4λe. 1 λ
1 answer:
Answer:
a. 3/4λ
d. 1/4λ
Explanation:
When the wavelength of the sound waves is λ and the two waves are having same frequency the waves are said to be out of phase if their phase difference is in the multiples of or 180°.
When the two waves are out of phase then their opposite maxima coincide at the same time resulting in the minimum amplitude of the resulting wave throughout.
- As we observe from the schematic that the a wave has sinusoidal pattern of variation and we get a maxima after each
of the distance.
- Here we have two speakers out of phase therefore on shifting one of the speakers by the odd multiples of
we have the maxima or the extreme amplitudes.
So, we must place the microphone at 3/4λ and 1/4λ to pickup the loudest sound.
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Answer:
9.98 m/s
Explanation:
The force acting on the particle is defined by the equation:
[N]
where x is the position in metres.
The acceleration can be found by using Newton's second law:
where
m = 150 g = 0.150 kg is the mass of the particle. Substituting into the equation,
[m/s^2]
When x = 3.14 m, the acceleration is:
Now we can find the final speed of the particle by using the suvat equation:
where
u = 8.00 m/s is the initial velocity
v is the final velocity
x = 3.14 m is the displacement
Solving for v,
And the speed is just the magnitude of the velocity, so 9.98 m/s.
The quantity that has a magnitude of zero when the ball is at the highest point in its trajectory is the vertical velocity.
In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity
, where 
- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration
directed downwards, and with initial velocity 
. Due to the presence of the acceleration g on the vertical direction (pointing in the opposite direction of the initial vertical velocity), the vertical velocity of the ball decreases as it goes higher, up to a point where it becomes zero and it reverses its direction: when the vertical velocity becomes zero, the ball has reached its maximum height.
In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity
- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration
Answer: (a) The gravitational force on the object at the North Pole of Neptune is 51.7N
(b) The apparent weight of the object at Neptune's equator is 50.4N
Explanation: Please see the attachments below
Explanation:
Mass of the Earth is equal to,
Any number can be written in the form of scientific notation as :
m is the real number
n is any integer
Mass of the earth can be written in the form of scientific notation as :
Here,
m = 5.97
n = 24
Hence, this is the required solution.