Given :
Thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center.
A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s².
To Find :
The magnitude of F.
Solution :
Torque on hoop is given by :
( Moment of Inertia of hoop is MR² )
Putting value of M, R and α in above equation, we get :

Therefore, the magnitude of force F is 25 N.
Hence, this is the required solution.
The two systems that work together to deliver oxygen are D, respiratory and cardiovascular
Answer:

Explanation:
Given that,
The radius of sphere, r = 0.3 m
Distance from the center of the sphere to the point P, x = 0.5 m
Electric field at point P,
(radially outward)
The maximum electric field is at the surface of the sphere. We know that the electric field is inversely proportional to the distance. So,




So, the magnitude of the electric field due to this sphere is 41666.66 N/C. Hence, this is the required solution.
Answer:
Total charge flow through the cooker is 21600 C
Explanation:
As we know that the current flow through the cooker is given by Ohm's law
here it is given as




now the charge flow through it is given as

total time is t = 8 hours


The pressure needed in PSI = Pounds of force needed divided by the cylinder Area
The Cylinder rod Area is 21.19 sq inches
Thus, the pressure= 6800/21.19
= 320.91 PSI