Question

An egg falls from a nest at a height of 4m. What speed will it have when it is 1m from the ground? Neglect air resistance and take g as 9.8m/s^2​

Answer 1

Answer: 7.66 m/s

Explanation:

This situation is related to free fall (vertical motion). Hence, this can be considered a one-dimension problem and we can use the following equation:

$V^{2}=V_{o}^{2}+2gd$

Where:

$V$ is the final velocity of the egg at the asked height

$V_{o}=0 m/s$ is the initial velocity of the egg

$g=9.8 m/s^{2}$ is the acceleration due gravity

$d=4 m- 1m= 3m$ is the distance at which the egg is from the nest, when it is $1 m$ from the ground

Isolating $V$:

$V=\sqrt{V_{o}^{2}+2gd}$

Substituting the known values:

$V=\sqrt{2(9.8 m/s^{2})(3 m)}$

$V=7.66 m/s$ This is the final velocity of the egg