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aniked [119]
2 years ago
9

The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If th

e trials were run on a real track with real gliders, using stopwatches and meter sticks for measurement, how might the data compare? Check all that apply.
- There would be variables that would be hard to control, leading to less reliable data.
- The data would be just as valid if it were recorded with a stopwatch.
- Meter sticks may lack precision or may be read incorrectly.
- Real glider data may vary since real collisions may involve loss of energy.
- Human error in recording or plotting the data could be a factor.
- Controlling real glider velocities by hand would be just as accurate as simulation controls.
Physics
2 answers:
wolverine [178]2 years ago
6 1

Answer:

1,3,5 are the actual correct answers, i just did the test

Explanation:

DiKsa [7]2 years ago
6 0
<h2><u>Answer:</u></h2>

The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If the trials were run on a real track with real gliders, using stopwatches and meter sticks for measurement, the data compared by the following statements:

1. (There would be variables that would be hard to control, leading to less reliable data.)

3. (Meter sticks may lack precision or may be read incorrectly.)

4. (Real glider data may vary since real collisions may involve loss of energy.)

5. (Human error in recording or plotting the data could be a factor.)


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2 years ago
Of waterfalls with a height of more than 50 m , Niagara Falls in Canada has the highest flow rate of any waterfall in the world.
Vinil7 [7]

Answer:

Power output: W=1426.9MW

Explanation:

The power output of the falls is given mainly by its change in potential energy:

Q=-P_{tot}=-(P_{2}-P_{1})

The potential energy for any point can be calculated as:

P=m*g*h

If we consider the base of the falls to be the reference height, at point 2 h=0, so P2=0, and height at point 1 equals 52m:

Q=P_{1}=m*g*h

If we replace m with the mass rate M we obtain the rate of change in potential energy over time, so the power generated:

W=M*g*h=2.8*10^{3}m^{3}/s*1*10^{3}kg/m^{3}*9.8m/s^{2}*52m =1426.9MW

5 0
2 years ago
A 5-ft-tall person walks away from the wall at a rate of 2 ft/sec. A spotlight is located on the ground 40 ft from the wall. How
AveGali [126]

Answer:

The rate of change of the height is - 4 ft/s

Solution:

As per the question:

Height of the person, y = 5 ft

The rate at which the person walks away, \frac{dx}{dt} = 4\ ft/s

Distance of the spotlight from the wall, x = 40 ft

Now,

To calculate the rate of change in the height, \frac{dy}{dt} of the person when, x = 10 m:

From fig 1.

\Delta ABC[\tex] ≈ [tex]\Delta PQC[\tex]Thus[tex]\frac{BC}{AB} = \frac{PQ}{QC}

\frac{y}{40} = \frac{5}{x}

xy = 200                                                                       (1)

Differentiating the above eqn w.r.t time t:

x\frac{dy}{dt} + y\frac{dx}{dt} = 0

Thus

\frac{dy}{dt} = - \frac{y}{x}\frac{dx}{dt}              (2)

From eqn (1):

When x = 10 ft

10y = 200

y = 20 ft

Using eqn (2):

\frac{dy}{dt} = - \frac{20}{10}\times 2 = - 4\ ft

8 0
2 years ago
The ends of a massless rope are attached to two stationary objects (e.g., two trees or two cars) so that the rope makes a straig
Virty [35]

Answer:

1. The tension in the rope is everywhere the same.

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3. The forces exerted on the two objects by the rope must be in opposite directions.

Explanation:

"Massless ropes" do not have a<em> "net force"</em> which means that it is able to transmit the force from one end of the rope to the other end, perfectly. It is known for its property of having a total force of zero. In order to attain this property, the magnitude of the forces exerted on the two stationary objects by the rope are the same and in opposite direction. <u>So this explains number 2 & 3 answers.</u>

Since the objects that are held by the rope are stationary, then this means that the tension in the rope is also stationary. This means that the tension in the rope everywhere is the same (provided that the rope is still or in a straight line, as stated in the situation above, and is being held by two points). <u>So, this explains number 1.</u>

6 0
2 years ago
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