Steam at a pressure of 15 bar and a temperature of 320oC is contained in a large vessel. Connected to the vessel through a valve
is a turbine followed by a small initially evacuated tank with a volume of 0.6 m3. When emergency power is required, the valve is opened and the tank fills with steam until the pressure is 15 bar. The temperature in the tank is then 400oC. The filling process takes place adiabatically and kinetic and potential energy effects are negligible. Determine the amount of work developed by the turbine, in kJ.
1 answer:
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Answer:
(a) Steel rod:
Copper rod:
(b) Steel rod:
Copper rod:
Explanation:
Length of each rod = 0.75 m
Diameter of each rod = 1.50 cm = 0.015 m
Tensile force exerted = 4000 N
(a) Strain is given as the ratio of change in length to the original length of a body. Mathematically, it is given as
Strain =
where Y = Young modulus
F = Fore applied
A = Cross sectional area
For the steel rod:
Y = 200 000 000 000
F = 4000N
A = (r = d/2 = 0.015/2 = 0.0075 m)
=> A =
=> A = 0.000177
∴
For the copper rod:
Y = 120 000 000 000 N/m²
F = 4000N
A = (r = d/2 = 0.015/2 = 0.0075 m)
=> A =
=> A = 0.000177
(b) We can find the elongation by multiplying the Strain by the original length of the rods:
Elongation = Strain * Length
For the steel rod:
Elongation =
For the copper rod:
Elongation =
Answer:
The acceleration is found as:
a = 1000 km/h²
Explanation:
Initial speed of the plane = 450 km/h
Final speed of the plane = 750 km/h
Time taken = 0.3 h
Acceleration can be defined as the change of speed of the object divided by the time taken to bring that change
Acceleration is given as:
where v(f) = 750 km/h , v(i) = 450 km/h , t = 0.3 h
Substitute the values in the equation of acceleration
This is the found result