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bazaltina [42]
2 years ago
5

A diver is is pushed upwards by a diving board. She weighs 739 N and accelerates from rest to a speed of 4.60 m/s while moving 0

.250 m upward.
(A) Compute the average force exerted on the diver by the diving board.
(B) Find the change in kinetic energy. This is equivalent to the net work done on the diver.
Physics
1 answer:
gavmur [86]2 years ago
8 0

Answer:

Answer A

Explanation:

It seems more likely

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The two major problems with most motor vehicles are that they burn fossil fuels and _____________.
Citrus2011 [14]

Answer:

A. Create radioactive waste i believe

Explanation:

8 0
2 years ago
Read 2 more answers
The power rating of an electric lawn mower is 2000 watts if lawnmower is used for 120 seconds how many joules of work van it do
Scorpion4ik [409]
1 watt = 1 joule/sec

2,000 watts = 2,000 joules/sec

                     (2,000 joule/sec) x (120 sec)

                  = (2,000 x 120)  (joule-sec/sec)

                  =   240,000 joules .
        
4 0
2 years ago
A sister spins her brother in a circle of radius R at angular speed wi. Then the sister decreases her angular speed
Igoryamba

Answer:

The change in the centripetal acceleration of the brother,

                               Δa = V₂²/R - V₁²/R

Explanation:

Given data,

A sister spins her brother in a circle of radius, R

The angular velocity of the brother, ω₁ = V₁/R

The angular velocity of the brother, ω₂ = V₂/R

The centripetal acceleration is given by the relation

                                 a = V²/R

Therefore change in the centripetal acceleration of the brother,

                              Δa = V₂²/R - V₁²/R                                    

6 0
2 years ago
Martha was leaning out of the window on the second floor of her house and speaking to Steve. Suddenly, her glasses slipped from
DiKsa [7]

Answer:

s = 23.72 m

v = 21.56 m/s²  

Explanation:

given

time to reach the ground (t) = 2.2 second

we know that

a) s = u t + 0.5 g t²

   u = 0 m/s

   g = 9.8 m/s²

   s = 0 + 0.5 × 9.8 × 2.2²

  s = 23.72 m

b) impact velocity

      v = √(2gh)

      v = √(2× 9.8 × 23.72)    

      v =  √464.912

      v = 21.56 m/s²  

6 0
2 years ago
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end
iragen [17]

Answer:

The workdone is  W_d =-4400J

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

            The force is on the force gauge  F = 2750 N

             The distance that Magnus pulled the bus  d = 1.60m

Generally  the workdone by the tension force on Magnus is

                  Workdone = Force * displacement \ in \ the \ direction \ of \ force

                     W_d = F * (-d)

This negative sign show that is tension force  is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

                   Workdone  =  - 2750 * 1.60

                                     =-4400 J

7 0
2 years ago
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