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antiseptic1488 [7]
2 years ago
11

Two parallel wires carry a current I in the same direction. Midway between these wires is a third wire, also parallel to the oth

er two, which carries a current 0.5 I, but in the direction opposite from the first two wires. Two more wires with 0.5 I, in the same direct as the third wire, are placed the same distance as the third wire but on either side of the first two wires. In which direction are the net forces on the outer wires?

Physics
2 answers:
Troyanec [42]2 years ago
8 0

Answer:

[ Find the attached file ]

First i draw a figure showing the condition, I had taken attractive force as +ve and repulsive force as - ve and thereafter calculating net force on outer left wire due to other wires, net force comes out to be - ve which tells us that force is repulsive, hence direction of force is away from wire as shown in figure.

Luda [366]2 years ago
4 0

Answer:

Force is repulsive hence direction of force is away from wire

Explanation:

The first thing will be to draw a figure showing the condition,

Lets takeI attractive force as +ve and repulsive force as - ve and thereafter calculating net force on outer left wire due to other wires, net force comes out to be - ve which tells us that force is repulsive, hence direction of force is away from wire as shown in figure in the attachment.

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Answer:Thus, The magnetic field around a current-carrying wire is <u><em>directly</em></u>  proportional to the current and <u><em>inversely</em></u>  proportional to the distance from the wire.  If the current triples while the distance doubles, the strength of the magnetic field increases by <u><em>one and half (1.5)</em></u> times.

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B'=\frac{\mu _oI'}{2\pi r'}=\frac{\mu _o3I}{2\pi 2r}=1.5B

Thus If the current triples while the distance doubles, the strength of the magnetic field increases by <u><em>one and half (1.5)</em></u> times.

   

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