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Anna007 [38]
2 years ago
5

As you know, loudspeakers are used for communication at sporting events, and in schools or supermarkets. Research loudspeakers o

n the Web. Describe the components of a speaker and explain how it produces sound. In particular, explain how the force on a current-carrying wire in a magnetic field is used to make a speaker operate.
Physics
1 answer:
Ivahew [28]2 years ago
4 0

Sound is invisible, but sometimes we can feel it. when a kettle-drum is thumped with a stick that time the tight drum skin moving up and down very quickly for some time and then it pumped sound waves into the air. Loudspeakers also work in a similar manner.

components of a speaker:

Electromagnet

In order to translate an electrical signal into an audible sound, an electromagnet is used in looudspeakers

 Suspension

suspension is used to  center the voice coil in the gap of the magnet and it exerts a restoring force to keep it there. suspension is used to limits the maximum mechanical excursion of the diaphragm and voice coil.

voice Coil

Voice coil is a coil of wire which is attached to the apex of a loudspeaker cone. It provides the motive force to the cone by the reaction of a magnetic field to the current passing through it.

Cone

In a  loudspeaker, a  thin, semi-rigid membrane attached to the voice coil, which moves in a magnetic gap due to which it vibrates  and produced sound. It is known as diaphragm and It can also be called a cone, though not all speaker diaphragms are cone-shaped.

Surround

surround is also known as front suspension. surround is used to join the cone to the chassis. Together with the suspension it controls the cone excursion, and it is also used to  determine how energy which is  travelling through the cone is absorbed, and how the speaker limits when it reaches the ends of its travel.

Dustcap

dustcap is used to protect the voice coil from dust and dirt. It is a part of the cone.

How speaker work

The outer part of the cone is fastened to the outer part of the loudspeaker's circular metal rim. The inner part is fixed to  voice coil that sits just in front of a permanent magnet . When loudspeaker is hooked up to a stereo, electrical signals feed through the speaker cables into the coil. It will convert the coil into an electromagnet magnet . when electricity flows back and forth in the cables, the electromagnet either repels or attract the permanent magnet. This moves the coil back and forth, and it pull and push the loudspeaker cone. Like a drum skin vibrating back and forth, the moving cone pumps sounds out into the air.In this way loudspeakers works.

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"Apparent magnitude" means how bright a star looks to
a person on Earth.

-- The star that appears brightest is the one with the
lowest-number apparent magnitude . . . Star-C, at -4 .

-- All of them are visible from Earth, but may require some 'help'. 
The dimmest stars visible with good human eyes under dark,
non-polluted skies are those with apparent magnitude around 6.
Stars B and C would be visible to the unaided eye, but Star-A
would require binoculars.
Around here, a few miles outside of the Chicago city limits, we're
lucky to see Magnitude-4 without binoculars.

-- It's not possible to determine which star has the highest luminosity.
The apparent magnitude depends on the star's distance from Earth
as well as its luminosity.
A flashlight 3 feet from your face appears much brighter than any
star, although any star is more luminous than the flashlight. 
Distance from you has a lot to do with it.
_____________________________________________

"Absolute magnitude" means how bright each star would appear
to a person on Earth if all stars were at the same distance from us.
(The distance happens to be 32.6 light years.)  It only depends on
the star's real luminosity, not on its distance.

-- It's not possible to determine which star appears brightest.
Star-C (absolute -7) would appear brightest if all stars were
equal distances from us.  But a flashlight ... which has a huge-
number absolute magnitude because we couldn't see at all from
32.6 light years away ... can appear very bright from 3 feet in
front of your face.

-- They're all visible from Earth, but a star with absolute magnitude
greater than 6 would need binoculars (or better) to be visible.

-- Yes, if you know a star's absolute magnitude, then you know its
luminosity.  The lowest-number absolute magnitudes are the ones
that would appear brightest if all stars were the same distance from
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6 0
2 years ago
"The drawing shows three layers of different materials, with air above and below the layers. The interfaces between the layers a
My name is Ann [436]

Answer:

Angle of incidence that entered material b= 63.1°

Angle of incidence between a and b = 55.9°

Explanation: Using the formular:

n1sintheta1= n2sintheta2

The light ray which enters material B will be

1.4Sin72.8° = 1.5Sin theta

1.3373= 1.5Sintheta

sintheta = 1.3373/1.5

Sin^-1 0.8916 = Theta

63.1 = theta

When the ray hits interface with material a

1.5Sin63.1 = 1.3 Sin theta

1.3374 = 1.3Sin theta

Sintheta= 1.3374/1.3

Sin theta = 1.0877

There will be total reflection off the boundary b c because sin theta exceeded 1 in value.

The equation should be

1.4sin63.1 = 1.4 sin theta

Sin theta=72.8°

When the ray hits air-c boundary:

1.4sin72.8=1.00sin theta

Sin theta=1.3374/1 =1.3374

There is total reflection.

In material a,the ray will:

1.3sin72.8° = 1.00sin theta

There will be total reflection when the ray hits a-b boundary.

1.3sin72.8= 1.5sintheta

Sin theta= 1.2419/ 1.5

Sin theta =0.8279

Theta= Sin^-10.8279= 55.88°

When ray hits c-air boundary

1.4sin63.1= 1.00sintheta

1.2485= sin theta = Toal reflection.

Therefore when the ray of light pass through the layers of material a, b and c the boundary with air on top and bottom will be total reflection.

7 0
2 years ago
A car drives off a cliff next to a river at a speed of 30 m/s and lands on the bank on theother side. The road above the cliff i
dezoksy [38]

Answer:1.301 s

Explanation:

Given

Initial Velocity(u)=30 m/s

Height of cliff=8.3 m

Time taken to cover 8.3 m

h=ut+\frac{at^2}{2}

here Initial vertical velocity is 0

8.3=\frac{gt^2}{2}

t^2=1.69

t=1.301 s

Horizontal distance

R=u\times t

R=30\times 1.301=39.04 m

7 0
2 years ago
The potential energy of a 40 kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?
Fynjy0 [20]
The formula for potential energy is PE=mgh
It can have that high of a potential energy if it's relative height what super high.
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2 years ago
Water is kept in a vessel at a temperature of 100°C. What would happen if a metal ball having a temperature of 30°C is dropped i
lesya [120]

Answer:

there will be a heat flow from water to the metal ball...

3 0
2 years ago
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