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Dmitry_Shevchenko [17]

2 years ago

13

A flat rectangular loop of wire carrying a 4.0-a current is placed in a uniform 0.60-t magnetic field. the magnitude of the torq

ue acting on this loop when the plane of the loop makes a 30° angle with the field is measured to be 1.1 n ∙ m. what is the area of this loop?

1 answer:

ZanzabumX [31]2 years ago

6 0

Torque on a closed current carrying loop is given by formula

$T = NiABsin\theta$

here

N = number of turns = 1

i = current = 4 A

A = area of the loop

B = magnetic field = 0.60 T

$\theta$ = angle between normal of the plane and magnetic field = 90 - 30 = 60 degree

Now we will have

$1.1 = 1* 4 * A * 0.60* sin60$

$1.1 = 2.078*A$

$A = 0.53 m^2$

So area of the loop is 0.53 m^2

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Uranus (mass = 8.68 x 1025 kg) and

Pepsi [2]

Answer:129,398,203.7 m

Explanation:

According to Newton's law of Universal Gravitation, the force $F$ exerted between two bodies of masses $M$ and $m$ and separated by a distance $d$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{Mm}{d^2}$ (1)

Where:

$F=2.28(10)^{19} N$ is the gravitational force

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the gravitational constant

$M=8.68(10)^{25} kg$ is the mass of Uranus

$m=6.59(10)^{19} kg$ is the mass of Uranu's moon, Mirana

$d$ is the distance between Uranus and its moon

Isolating $d$ :

$d=\sqrt{\frac{GMm}{F}}$ (2)

$d=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(8.68(10)^{25} kg)(6.59(10)^{19} kg)}{2.28(10)^{19} N}}$ (3)

Finally:

$d=129,398,203.7 m$

5 0

1 year ago

A basketball is tossed upwards with a speed of 5.0\,\dfrac{\text m}{\text s}5.0 s m 5, point, 0, start fraction, start text, m

Hatshy [7]

Answer:

The last one

Explanation:

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2 years ago

A rotating beacon is located 2 miles out in the water. Let A be the point on the shore that is closest to the beacon. As the bea

Mice21 [21]

Answer:

$v = 3369.2 m/s$

Explanation:

As we know that Beacon is rotating with angular speed

$f = 10 rev/min$

so we have

$\omega = 2\pi f$

$\omega = 2\pi(\frac{10}{60})$

$\omega = 1.047 rad/s$

now we know that

$v = r \omega$

here we will have

$r = 2 miles = 2(1609 m)$

$r = 3218 m$

so we have

$v = 3218(1.047)$

$v = 3369.2 m/s$

6 0

1 year ago

Lucille is finding it difficult to play soccer after school. Her doctor thinks that her cells might not be getting enough oxygen

Bad White [126]

Explanation:

Lucile

Lucile cells needs a huge abundance of glucose and oxygen supply in order for her body to function properly and participate in a soccer game.

Playing a soccer game is energy demanding. The body's energy supply is met by the metabolism of glucose in cells using oxygen.

The problem with Lucille's respiratory and circulatory system can make it difficult for her to take part in soccer game because the needed energy would not be available for her to participate in the game.

Respiratory system is saddled with the responsibility of bringing enough oxygen to body system through gaseous exchange and metabolism.
The circulatory system carries the oxygen to the different body cells to where they are need. It also takes the deoxygenated blood to where they can get oxygenated.
We can clearly see that if respiratory and circulatory systems are not functioning well, Lucille's cells will not be able to furnish her with the much needed energy.

Ezra

Ezra needs energy to play basketball well. The energy is produced via the glucose in the starch and the oxygen from breathing.

When starch is broken down, glucose is produced.

How it works;

The digestive, circulatory and respiratory systems are all important here. They ensure that Ezra gets the needed energy from the food he is eating. Proteins also have the capability of producing energy when there is shortage of starch in the body.

Ezra's digestive system through a couple of processes releases glucose from the food he eats especially the bread in the sandwich.

The glucose is stored in the body and made available for use when in need.

The glucose is used to produce energy.

When Ezra breathes, the circulatory system ensures gaseous exchange with the surroundings. Oxygen rich blood is taken the cells where they combine with glucose for their metabolic actions. Oxygen deficient bloods are carried away.

In the cell, a special apparatus called the mitochondria combines glucose with oxygen and energy is liberated. The energy is used by Ezra to run while playing basketball

learn more:

Cellular respiration brainly.com/question/3447259

#learnwithBrainly

7 0

2 years ago

A package is dropped from a helicopter that is descending steadily at a speed v0. After t seconds have elapsed, consider the fol

qaws [65]

Answer:

Part a)

$v = \sqrt{v_o^2 + g^2t^2}$

Part b)

$d = \frac{1}{2}gt^2$

Part c)

$v_f = v_o - gt$

Part d)

$d = \frac{1}{2}gt^2$

Explanation:

Part a)

As we know that speed of package is same as that of helicopter in horizontal direction

So after time "t" the velocity in x direction will remain constant while in Y direction it will go free fall

So we have

$v_y = -gt$

$v = \sqrt{v_x^2 + v_y^2}$

$v = \sqrt{v_o^2 + g^2t^2}$

Part b)

Distance from helicopter is same as the distance of free fall

so we will have

$d = \frac{1}{2}gt^2$

Part c)

If helicopter is rising upwards with uniform speed

then final speed of the package after time t is given as

$v_f = v_i + at$

$v_f = v_o - gt$

Part d)

distance from helicopter

$d = \frac{1}{2}gt^2$

8 0

2 years ago

Read 2 more answers