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Irina-Kira [14]
2 years ago
5

Enrico says that positive charge is created when you rub a glass rod with silk, and that negative charge is simply the absence o

f positive charge. Rosetta says that negative charge is created and that positive charge is the absence of positive charge. (She has heard that Ben Franklin should have reversed the signs he associated with the charges.) Which one, if either, is correct1. Enrico, because there really is only one kind of charge.2. Rosetta, because there really is only one kind of charge.3. Neither: although no charge is present originally, both types of charge are created through friction.4. Both: only one type of charge is created by friction at any one time.5. Neither: both negative and positive charge are present simultaneously in all solid materials on Earth.
Physics
1 answer:
lisabon 2012 [21]2 years ago
7 0

Answer:5 Neither: both negative and positive charge are present simultaneously in all solid materials on Earth

Explanation:

When we rub a glass rod with silk cloth then some of the electrons from glass rods are stripped away to the silk cloth. These electrons are loosely bound to the silk rod that is why they easily transferred to silk cloth.  

There is no net charge because the charge is induced when we rub the cloth and charge are separated therefore we able to notice these charges.

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Answer:

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difference in the atomic mass of helium = 4.03176-4.002602 = 0.029158

fraction of mass lost = \dfrac{0.029158}{4.03176}= 0.00723

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1 year ago
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 And from Ohm law

                           I_s =\frac{ V}{R_T}

                            I_s  = \frac{V_0}{R_1 +R_2} ---(1)

The mathematical representation of the two resistors connected in parallel  is

                    R_T = \frac{1}{R_1} +\frac{1}{R_2}

                          = \frac{R_1 R_2}{R_1 +R_2}

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     Dividing equation 2 with equation 1

       =>                 \frac{10I_s}{I_s} =\frac{\frac{V_0 (R_1 +R_2)}{R_1 R_2}}{\frac{V_0}{R_1 +R_2}}

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We are told that    r = \frac{R_1}{R_2} \ \ \ \ \  = > R_1 = rR_2

From equation 3  

                            10 = \frac{(1-r)^2}{r}

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=> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ r^2 -8r+1 = 0

Using the quadratic formula

                             r =\frac{-b\pm \sqrt{(b^2 - 4ac)} }{2a}

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                              =  \frac{8 \pm\sqrt{((-8)^2- (4*1*1))} }{2*1}

                               r= \frac{8+ \sqrt{60} }{2}  \ or \  r = \frac{8 - \sqrt{60} }{2}

                              r = \ 7.87\ or \  r \  = \ 0.127

Now  r =  0.127 because it is the least value among the obtained values

                               

                                   

                             

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