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den301095 [7]
2 years ago
5

The pesticide DDT was first made by a chemical company in 1939 and became widely used worldwide. Evidence that DDT builds up in

animal tissues and may cause health problems such as cancer and damage to organs, as detailed in Rachel Carson’s book Silent Spring, resulted in DDT being banned in the US in 1972. How do you suppose science and society were affected by the ban of DDT?
Physics
2 answers:
Anna71 [15]2 years ago
4 0

It worked

DDT or Dichlorodiphenyltrichloroethane is a kind of pesticide that's colorless and tasteless in form. It has been a known pesticide used for agricultural purposes in the US.It was banned because of its known effects and impact to both humans and other living organisms. A book published by Rachel Carson entitled "Silent Spring" exposed the truth that DDT can cause cancer to humans and is an agricultural threat to wildlife, particularly birds like the bald eagle and the peregrine falcon who were almost near-extinction before the said pesticide was banned.



Serjik [45]2 years ago
4 0

DDT or Dichlorodiphenyltrichloroethane<span> is a kind of pesticide that's colorless and tastless in form. It has been a known pesticide used for agricultural purposes in the US. 
</span>
It was banned because of its known effects and impact to both humans and other living organisms. A book published by Rachel Carson entitled "Silent Spring" exposed the truth that DDT can cause cancer to humans and is an agricultural threat to wildlife, particularly birds like the bald eagle and the peregrine falcon who were almost near-extinction before the said pesticide was banned. 

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A package is dropped from a helicopter that is descending steadily at a speed v0. After t seconds have elapsed, consider the fol
qaws [65]

Answer:

Part a)

v = \sqrt{v_o^2 + g^2t^2}

Part b)

d = \frac{1}{2}gt^2

Part c)

v_f = v_o - gt

Part d)

d = \frac{1}{2}gt^2

Explanation:

Part a)

As we know that speed of package is same as that of helicopter in horizontal direction

So after time "t" the velocity in x direction will remain constant while in Y direction it will go free fall

So we have

v_y = -gt

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{v_o^2 + g^2t^2}

Part b)

Distance from helicopter is same as the distance of free fall

so we will have

d = \frac{1}{2}gt^2

Part c)

If helicopter is rising upwards with uniform speed

then final speed of the package after time t is given as

v_f = v_i + at

v_f = v_o - gt

Part d)

distance from helicopter

d = \frac{1}{2}gt^2

8 0
2 years ago
Read 2 more answers
Kenny and Candy decided to sit on a see-saw while visiting a local play park. Candy, of mass
pochemuha

Answer:

(i) 208 cm from the pivot

(ii) Move further from the pivot

Explanation:

(i) Sum of the moments about the pivot of the seesaw is zero.

∑τ = Iα

(50 kg) (10 N/kg) (2.5 m) + (60 kg) (10 N/kg) x = 0

1250 Nm + 600 N x = 0

x = -2.08 m

Kenny should sit 208 cm on the other side of the pivot.

(ii) To increase the torque, Kenny should move away from the pivot.

4 0
2 years ago
Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
horsena [70]

Answer:

a)106.48 x 10⁵ kg.m²

b)144.97 x 10⁵  kgm² s⁻¹  

Explanation:

a)Given

m = 5500 kg

l = 44 m

Moment of inertia of one blade

I= 1/3 x m l²

where m is mass of the blade

l is length of each blade.

Putting all the required values, moment of inertia of one blade will be

I= 1/3 x 5500 x 44²  

I= 35.49 x 10⁵ kg.m²

Moment of inertia of 3 blades

I= 3 x 35.49 x 10⁵ kg.m²

I= 106.48 x 10⁵ kg.m²

b) Angular momentum 'L' is given by

L =I x ω

where,

I= moment of inertia of turbine i.e  106.48 x 10⁵ kg.m²

ω=angular velocity =2π f

f is frequency of rotation of blade i.e  13 rpm

f = 13 rpm=>= 13 / 60 revolution per second

ω = 2π f =>  2π  x  13 / 60 rad / s

L=I x ω =>106.48 x 10⁵ x   2π  x  13 / 60

  = 144.97 x 10⁵  kgm² s⁻¹    

7 0
1 year ago
A punted football is observed to have velocity components vhorizontal = 15 m/s to the right and vvertical = 1.25 m/s directed do
enot [183]

Answer:

v₀ₓ = 15 m / s,  v_{oy} = 5.2 m / s

v = 15.87 m / s ,   θ = 19.1

Explanation:

This is a projectile launch problem. The horizontal speed that is constant throughout the entire path is worth 15 m / s, instead the vertical speed changes in value due to the acceleration of gravity, let's look for the initial vertical speed

                      Vy² =v_{oy}² - 2 g y

                      v_{oy}² = v_{y}² + 2 g y

                       v_{oy} = √ (v_{y}² + 2 gy

Let's calculate

                    v_{oy} = √ (1.25² + 2 9.8 1.3)

                    v_{oy} = √ (27.04)

                    v_{oy} = 5.2 m / s

 The initial speed can be calculated by the initial speed

                   v = √ v₀ₓ² + v_{oy}²

                   v = RA (15² + 5.2²)

                   v = 15.87 m / s

We look for the angle with trigonometry

                 tan θ = voy / vox

                 θ = tan⁻¹ I'm going / vox

                θ = tan⁻¹ 5.2 / 15

                θ = 19.1

The answer is

              v₀ₓ = 15 m / s

              v_{oy} = 5.2 m / s

5 0
1 year ago
3) 4 electrons are placed - one electron per corner - at the corners of a square of side 1 meter. One fixed proton is placed in
Eduardwww [97]

Explanation:

3

i believe that they are all going at 3.2 meters each, I did 4 times 0.8

4 0
2 years ago
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