Answer: The comet's average distance from the sun is 17.6AU
Explanation:
From Kepler's 3rd Law, P^2=a^3
Where P is period in years
and a is length of semi-major axis or the average distance of the comet to the sun.
Given the orbital period to be 74 years
74^2 =a^3
5476 = a^3
Cube root of 5476 =a
17.626 = a
Approximately a= 17.6 AU
Explanation:
It is given that,
The horizontal speed of a cliff diver, 
It reaches the water below 2.00 s later, t = 2 s
Let 
is the distance where the diver hit the water. It can be calculated as follows :
Let 
is the height of the cliff. It can be calculated using second equation of motion as follows :
So, the cliff is 19.6 m high and it will hit the water at a distance of 19.6 m.
Answer:
The force applied on the big piston is 1306.67 N
Explanation:
Given;
force applied on small piston, F₁ = 200 N
diameter of the small piston, d₁ = 4.37 cm
radius of the small piston, r₁ = d₁/2 = 2.185 cm
Area of the small piston, A₁ = πr₁² = π(2.185 cm)² = 15 cm²
Area of the big piston, A₂ = 98 cm²
The pressure of the piston is given by;
Where;
F₂ is the force on big piston
Therefore, the force applied on the big piston is 1306.67 N
Either theory or evidence
Answer:
75.6J
Explanation:
Hi!
To solve this problem we must use the first law of thermodynamics that states that the heat required to heat the air is the difference between the energy levels of the air when it enters and when it leaves the body,
Given the above we have the following equation.
Q=(m)(h2)-(m)(h1)
where
m=mass=1.3×10−3kg.
h2= entalpy at 37C
h1= entalpy at -20C
Q=m(h2-h1)
remember that the enthalpy differences for the air can approximate the specific heat multiplied by the temperature difference
Q=mCp(T2-T1)
Cp= specific heat of air = 1020 J/kg⋅K
Q=(1.3×10−3)(1020)(37-(-20))=75.6J
